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Thepotemich [5.8K]
3 years ago
10

F(x)=4x+4;{-2,-1,0,1,2}

Mathematics
2 answers:
vlabodo [156]3 years ago
7 0

Answer:

55 and the gravitational of a new one

Step-by-step explanation:

7th grade and the gravitational of a

GrogVix [38]3 years ago
3 0

Answer:

i need more info

Step-by-step explanation:

please comment on this to tell me all of said details

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How do i check 11z-5=9z+7
NARA [144]

Answer:

z= 6

Step-by-step explanation:

You check it by plugging the value, z, into the equation.

11(6)-5=9(6)+7

61=61

3 0
3 years ago
Read 2 more answers
Let f(x) = 4x2 + x + 1 and g(x) = x2 – 2. Find g(f(x)). Show each step of your work.<br> Help please
STatiana [176]
For the answer to the question above, 
<span>g(f(x)) = (4x^2 + x + 1)^2 - 2 </span>

<span>g(f(x)) = (16x^4 + 4x^3 + 4x^2 + 4x^3 + x^2 + x + 4x^2 + x + 1) - 2 </span>

<span>g(f(x)) = 16x^2 + 8x^3 + 9x^2 + 2x + 1 - 2 </span>

<span>g(f(x)) = 16x^2 + 8x^3 + 9x^2 + 2x - 1
I hope my answer helped you. Feel free to ask more questions. Have a nice day!</span>
6 0
2 years ago
Read 2 more answers
What is the equation of a line with a slope of 7 and a point (1, 8) on the line?
stira [4]
Slope: 7   given point: (1,8)

y = 7x + b          step 1 - plug in the slope in the formula
8 = 7(1) + b       step 2 - plug in the given point
8 = 7 + b           step 3 - simplify the expression
b = 1                 step 4 - solve for b
y = 7x + 1         step 5 - plug in b

formula: y = 7x + 1
6 0
3 years ago
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t
xz_007 [3.2K]

Full Question

A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.

Determine the spring constant k.

Answer:

Spring Constant = 1000Nm^-1

Step-by-step explanation:

Given

Mass = 10kg

Spring Extension = 9.8cm

Spring Constant K = Force/Extension

Force = Mass * Acceleration

Force = 10 * 9.8 = 9.8N

Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m

Spring constant = 98 / 0.098

Spring Constant = 1000Nm^-1

3 0
2 years ago
A 6 ft tall tent standing next to a cardboard box casts a 15 ft shadow. if the cardboard box casts a shadow that is 6 ft long th
ohaa [14]
What we know is that a 6 foot tall tent casts a 15 foot shadow. Lets represent that given this way: 6 = 15
So, the unknown (y), or what we want to know, is how tall the cardboard box if it has a 6 foot long shadow (noticeably the same height as the tent):
y = 6

6 = 15
y = 6

(6 x 6) / 15 = y
36 / 15 = y
2.4 = y

The height of the cardboard box is 2.4 feet.
4 0
3 years ago
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