All categories

3 years ago

A number cube is numbered 1 through 6. What is the theoretical probablity of rolling an even number?

2 answers:

8 0

It’s 1/2! Or you could say 3/6. This is because in 1-6 there are 3 even Numbers and that would be half of the 6 sides are even numbers! Hope this helps! :)

vesna_86 [32]3 years ago

5 0

A 3/6 of a chance because there’s 3 even numbers also 50% chance or 1/2 chance

You might be interested in

After 8 years, what is the total amount of a compound interest investment of$25,000 at 3% interes compounded quarteriy? A. 525.3

Artyom0805 [142]

I believe its D. Hope it helps you!

8 0

3 years ago

Select the correct answer. Which expression represents the series ? 1+5+25+125+625? creating and solving formulas for geometric

Art [367]

Answer:

The given series can be written as

∑ (5)^i

i = 0

We know that the series is

1+5+25+125+625

This is equal to

(5)^0 + (5)^1 + (5)^2 + (5)^3 + (5)^4

Thus,

For i from 0 to 4,

We get the general representation.

3 0

3 years ago

Efectuati calculele:

NNADVOKAT [17]

$\sqrt{(5 - 1)^{2}} + \sqrt{20}$

$\sqrt{4^{2}} + \sqrt{4 * 5}$

$\sqrt{16} + \sqrt{4} \sqrt{5} 
$

$4 + 2 \sqrt{5} 
$

$4\sqrt{5} + 2 \sqrt{5} 
$

$6 \sqrt{5}$

$\sqrt{(10 - 3)^{2}} + \sqrt{20 * 18}$

$\sqrt{7^{2}} + \sqrt{4 * 9 * 5 * 2}$

$\sqrt{49} + \sqrt{36 * 10}$

$7 + \sqrt{36}\sqrt{10}$

$7 + 6\sqrt{10}$

$7\sqrt{10} + 6\sqrt{10}$

$13\sqrt{10}$

$\sqrt[3]{(3 + 1)^{2}} - \sqrt{(3 - 2)x^{2}$

$\sqrt[3]{4^{2}} - \sqrt{x^{2}$

$\sqrt[3]{16} - x[tex] \\[tex] \sqrt[3]{8 * 2} - x$

$\sqrt[3]{8} \sqrt[3]{2} - x
$

$2\sqrt[3]{2} - x$

8 0

3 years ago

Y=-6x-4 as integer form

Maksim231197 [3]

Answer:

y=-24

Step-by-step explanation:

hope this will help you

3 0

3 years ago

20h - 8) - h = h - 16

Degger [83]

Answer:

C.h=infinitely many solution

6 0

3 years ago