A = 6x-11<br> g= 36<br> n = 7x - 27<br> Solve for x

How do I find the y intercept in a fraction

Furkat [3]

ANSWER:

Both functions have the same slope

The linear equation does not have a y-intercept

The table and the grahp express an equivalent function

STEP-BY-STEP EXPLANATION:

In order to compare, we must calculate the slope of the table, knowing that the equation in its slope and intercept form is the following:

$\begin{gathered} y=mx+b \\ \text{where m is the slope and b is y-intercept} \end{gathered}$

The formula to calculate the slope is the following:

$m=\frac{y_2-y_1}{x_2-x_1}$

The points are (-6, -9/2) and (4,3), replacing:

$m=\frac{3-(-\frac{9}{2})}{4-(-6)}=\frac{3+\frac{9}{2}}{4+6}=\frac{\frac{15}{2}}{10}=\frac{15}{20}=\frac{3}{4}$

The slope is 3/4

Now, for b

x = 4

y = 3

m = 3/4

replacing:

$\begin{gathered} 3=\frac{3}{4}\cdot4+b \\ b=3-3 \\ b=0 \end{gathered}$

The equation is:

$y=\frac{3}{4}x$

Therefore, the true statements are:

• Both functions have the same slope

,

• The linear equation does not have a y-intercept

,

• The table and the grahp express an equivalent function

8 0

10 months ago

Please help ill mark brainlyst please

kozerog [31]

Answer:

x = 8°

y = 21°

Step-by-step explanation:

27 + 3y = 90

3y = 63

y = 21°

x + 8x + 18 = 90

9x = 72

x = 8°

3 0

3 years ago

Lashonda is on the swim team. Each week she swims a total of 9000 meters. How many kilometers does she swim each week? Be sure t

svp [43]

Answer:

Rate is 9 kilometers (km)/week.

Step-by-step explanation:

9000 meters is 9 km (divide m by 1000 to get km)

4 0

2 years ago

Use differentials to estimate the amount of metal in a closed cylindrical can that is 26 cm high and 10 cm in diameter if the me

Afina-wow [57]

Answer:

The estimated amount of metal in the can is 87.96 cubic cm

Step-by-step explanation:

We can find the differential of volume from the volume of a cylinder equation given by

$V= \pi r^2 h$

Thus that way we will find the amount of metal that makes up the can.

Finding the differential.

A small change in volume is given by:

$dV =\cfrac{\partial V}{\partial h} dh + \cfrac{\partial V}{\partial r} dr$

So finding the partial derivatives we get

$dV =\pi r^2 dh + \pi 2r h dr$

$dV =\pi r^2 dh + 2\pi r h dr$

Evaluating the differential at the given information.

The height of the can is h = 26 cm, the diameter is 10 cm, which means the radius is half of it, that is r = 5 cm.

On the other hand the thickness of the side is 0.05 cm that represents dr = 0.05 cm, and the thickness on both top and bottom is 0.3 cm, thus dh = 0.3 cm +0.3 cm which give us 0.6 cm.

Replacing all those values on the differential we get

$dV =\pi 5^2 (0.6) + 2\pi (5) (26) (0.05)$

That give us

$V= 28 \pi \, cm^3$

Or in decimal value

$\boxed{dV= 87.96 \, cm^3}$

Thus the volume of metal in the can is 87.96 cubic cm.

6 0

3 years ago

CAN SOMEONE PLEASE PLEASE PLEASE HELP ME, YOU’LL GET FREE EASY POINTS IF YOU GIVE ME THE RIGHT ANSWER !!

bekas [8.4K]

Answer:

reflection across BC
the image of a vertex will coincide with its corresponding vertex
SSS: AB≅GB, AC≅GC, BC≅BC.

Step-by-step explanation:

We want to identify a rigid transformation that maps congruent triangles to one-another, to explain the coincidence of corresponding parts, and to identify the theorems that show congruence.

__

Triangles GBC and ABC share side BC. Whatever rigid transformation we use will leave segment BC invariant. Translation and rotation do not do that. The only possible transformation that will leave BC invariant is <em>reflection across line BC</em>.

__

In part 3, we show ∆GBC ≅ ∆ABC. That means vertices A and G are corresponding vertices. When we map the congruent figures onto each other, <em>corresponding parts are coincident</em>. That is, vertex G' (the image of vertex G) will coincide with vertex A.

__

The markings on the figure show the corresponding parts to be ...

side AB and side GB
side AC and side GC
angle ABC and angle GBC
angle BAC and angle BGC

And the reflexive property of congruence tells us BC corresponds to itself:

side BC and side BC

There are four available congruence theorems applicable to triangles that are not right triangles

SSS -- three pairs of corresponding sides
SAS -- two corresponding sides and the angle between
ASA -- two corresponding angles and the side between
AAS -- two corresponding angles and the side not between

We don't know which of these are in your notes, but we do know that all of them can be used. AAS can be used with two different sides. SAS can be used with two different angles.

SSS

Corresponding sides are listed above. Here, we list them again:

AB and GB; AC and GC; BC and BC

SAS

One use is with AB, BC, and angle ABC corresponding to GB, BC, and angle GBC.

Another use is with BA, AC, and angle BAC corresponding to BG, GC, and angle BGC.

ASA

Angles CAB and CBA, side AB corresponding to angles CGB and CBG, side GB.

AAS

One use is with angles CBA and CAB, side CB corresponding to angles CBG and CGB, side CB.

Another use is with angles CBA and CAB, side CA corresponding to angles CBG and CGB, side CG.

3 0

1 year ago

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A = 6x-11 g= 36 n = 7x - 27 Solve for x