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zvonat [6]
3 years ago
12

What's the complete factored form.5b^2(p-7)+7(p-7)​

Mathematics
1 answer:
kap26 [50]3 years ago
6 0

Answer:

The complete factored form in (p-7)(5b^2+7)

Step-by-step explanation:

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A tourist standing on the New York City coast sees the Statue of Liberty, which is 305 feet tall. She must tilt her head 9 degre
mixer [17]

Given:

Height of the Statue of Liberty = 305 feet

Angle of elevation = 9 degrees

To find:

The between the tourist and the Statue of Liberty.

Solution:

Using the given information, draw a figure as shown below.

In a right triangle,

\tan \theta=\dfrac{Perpendicular}{Base}

In the triangle ABC,

\tan 9^\circ=\dfrac{305}{x}

x=\dfrac{305}{\tan 9^\circ}

x=1925.6942

x\approx 1926

Therefore, the tourist is standing 1926 feet from the Statue of Liberty.

4 0
2 years ago
The half-life of radium-226 is 1600 years. Suppose we have a 27-mg sample.
slega [8]

A function m(t)= m₀e^(-rt) that models the mass remaining after t years is; m(t) = 27e^(-0.00043t)

The amount of sample that will remain after 4000 years is; 4.8357 mg

The number of years that it will take for only 17 mg of the sample to remain is;  1076 years

<h3>How to solve exponential decay function?</h3>

A) Using the model for radioactive decay;

m(t)= m₀e^(-rt)

where;

m₀ is initial mass

r is rate of growth

t is time

Thus, we are given;

m₀ = 27 mg

r = (In 2)/1600 = -0.00043 which shows a decrease by 0.00043

and so we have;

m(t) = 27e^(-0.00043t)

c) The amount that will remain after 4000 years is;

m(4000) = 27e^(-0.00043 * 4000)

m(4000) = 27 * 0.1791

m(4000) = 4.8357 mg

d) For 17 mg to remain;

17 = 27e^(-0.00043 * t)

17/27 = e^(-0.00043 * t)

In(17/27) = -0.00043 * t

-0.4626/-0.00043 = t

t = 1076 years

Read more about Exponential decay function at; brainly.com/question/27822382

#SPJ1

5 0
1 year ago
(2r^3-5r) - (r^3+5r)
kotykmax [81]

Answer:

r^3-10r

Answer Explanation:

4 0
3 years ago
Write a recursive formula for these sequences<br><br> 3,6,18,72,360,...<br><br><br> 5,9,18,34,59,...
Temka [501]
1) A(n+1)=2×A(n) where n1 = 3 and n greater than or equal to 1
Sorry I don't get the second one
8 0
3 years ago
Given f(x) = x2 + 5 and g(x) = x^2 , and h(x) = -2x <br>what is h(g(f(x)))=
jeyben [28]

Answer:

Step-by-step explanation:

f(x) = x^2 + 5

g(x^2 + 5) = (x^2 + 5)^2= x^4 + 5x^2 + 5x^2 + 25 = x^4 + 10x^2 + 25

h(x^4 + 10x^2 + 25)= -2(x^4 + 10x^2 + 25)

                                  -2x^4 - 20x^2 - 50

5 0
3 years ago
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