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zvonat [6]
3 years ago
12

What's the complete factored form.5b^2(p-7)+7(p-7)​

Mathematics
1 answer:
kap26 [50]3 years ago
6 0

Answer:

The complete factored form in (p-7)(5b^2+7)

Step-by-step explanation:

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a student government organization is selling christmas trees as a fundraiser. on friday, they sold five noble fir trees and thre
IRINA_888 [86]

Answer:

$60 for a noble fir, and $40 for a douglas fir

Step-by-step explanation:

Let x represent the number of noble fir trees

Let y represent the number of douglas fir trees

We can set up a system of equations to solve this problem

5x + 3y =  420  

12x + 9y = 1080      

We can use elimination method to solve this.  9 is a multiple of 3, so we'll multiply the first equation by -3 to get...

-15x - 9y = -1260

12x + 9y = 1080

Now add them together...

-3x = -180         now solve for x...

        x = 60

If x = 60, them

5(60) + 3y = 420        now solve for y

  300 + 3y = 420

      3y = 120

           y =  40

       

3 0
3 years ago
A school janitor has mopped
Tatiana [17]
1/3 of the classroom is mopped in five minutes, so the whole classroom (or one classroom) is mopped in 15 minutes
3 0
3 years ago
Read 2 more answers
Solve the equation for principal values of x. Express solutions in degrees.
timama [110]

Answer: i think is B=45

Step-by-step explanationx=45+360n,135+360n\\=45

3 0
3 years ago
Consider the following argument. If I get a Christmas bonus, I'll buy a stereo. If I sell my motorcycle, I'll buy a stereo. ∴ If
Nuetrik [128]

Answer:

p → r valid, proof by division into cases

q → r

∴ p ∨ q → r

Step-by-step explanation:

Let

p = "if I get a Christmas bonus,"

q = "if I sell my motorcycle,"

and

r = "I'll buy a stereo."

This can be written as:

If I get a Christmas bonus, I'll buy a stereo

p → r

If I sell my motorcycle, I'll buy a stereo

q → r

∴ If I get a Christmas bonus or I sell my motorcycle, then I'll buy a stereo.

∴ p ∨ q → r

To prove this argument we partition the argument into a group of smaller statements that together cover all of the original argument and then we prove each of the smaller statements. If you see the conclusion ∴ p ∨ q -> r so if the conclusion contains a conditional argument of form "If A1  or A2 or... or An then C ”, then we prove "If A1 then C", "If A2 then C" and so on upto "If An then C" . This depicts that the conclusion  C is true no matter which if the Ai holds true. This method is called proof by division into cases. In the given example, this takes the form:

p → r

q → r

p ∨ q

∴ r

Since proof by division into cases is an inference rule thus given argument is valid. Lets make a truth table to show if this argument is valid

p   q   r   p ∨ q   p → r    q → r    p ∨ q → r

0   0   0     0        1           1             1

0   0   1      0        0          0            0

0   1    0     1         1           0            0

0   1    1      1         0          1               1

1    0   0     1         0          1             0    

1    0   1      1         1           0            1    

1    1    0     1         0          0            0    

1    1    1      1         1           1              1    

An argument is valid if all of the premises are true, then the conclusion is true. So the truth table shows that the conclusion is true i.e. 1 where all premises are true i.e. 1. So the argument is valid.

Hence

p → r valid, proof by division into cases

q → r

∴ p ∨ q → r

4 0
3 years ago
What is the midpoint of AB with A(-1, 5) and B(6, -3) A (-4, 3.5) B (1, 2.5) C (2.5, 1) D (3.5, -4)
Alina [70]

Answer:

Option C (2.5, 1) is the right alternative.

Step-by-step explanation:

The given points are:

A = (-1, 5) = (x₁, y₁)

B = (6, -3) = (x₂, y₂)

Now,

The midpoint on X-axis is:

= \frac{x_1+x_2}{2}

= \frac{-1+6}{2}

= \frac{5}{2}

= 2.5

The midpoint on Y-axis is:

= \frac{y_1+y_2}{2}

= \frac{5+(-3)}{2}

= \frac{5-3}{2}

= \frac{2}{2}

= 1

Thus the midpoint of AB is "2.5, 1".

4 0
3 years ago
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