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AlexFokin [52]
3 years ago
15

What is the answer please help no links I will report

Mathematics
1 answer:
fomenos3 years ago
5 0
I found the answer. hehehehehehehehrheehrhrh

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Find the zeros of the polynomial function and state the multiplicity of each.
zheka24 [161]
\bf f(x) = 4(x + 7)^2(x - 7)^3\implies 0 = 4(x + 7)^2(x - 7)^3
\\\\\\
0=(x+7)^2(x-7)^3\implies 
\begin{cases}
0=(x+7)^7\\
\qquad 0=(x+7)(x+7)\\
\qquad -7=x\\
\qquad -7=x\\
----------\\
0=(x-7)^3\\
\qquad 0=(x-7)(x-7)(x-7)\\
\qquad 7=x\\
\qquad 7=x\\
\qquad 7=x
\end{cases}

the -7 is found there twice, so it has a multiplicity of 2
the +7 is there thrice, so it has multiplicity of 3
7 0
3 years ago
Which expression is equivalent to 2(3g – 4) - (8g + 3)?
Brilliant_brown [7]

Answer:

The Answer is D

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The graph of a linear equation passes through three of these points: (0, 5), (2, 2), (3, 1), and (4, -1). The point that the gra
dlinn [17]
Label the given points as follows:
A (0, 5)
B (2, 2)
C (3, 1)
D (4, -1)

The straight line has a constant slope. Therefore it should have the same value when any two of the four points are used to calculate the slope.

Try A and B:
Slope = (2 - 5)/(2 - 0) = -3/2

Try A and C:
Slope = (1 - 5)/(3 - 0) = -4/3

Try A and D.
Slope = (-1 - 5)/(4 - 0) = -3/2

Try B and D.
Slope = (-1 - 2)/(4 - 2) = -3/2

Clearly, C does not lie on the straight line.

Answer:  The point that the graph does not pass through is (3,1). 
5 0
3 years ago
In a survey, 150 shoppers were asked whether they have access to a computer at home and if they have a personal e-mail account.
rosijanka [135]
I don't know what you are talking about please re word the question its really hard to understand what your asking.
8 0
3 years ago
If the area around the vegetable garden is of uniform width (labeled with x) and the dimensions of the vegetable garden is 45 fe
Nady [450]
Area of Rectangle = Width × Length

Vegetable Garden
Width = 20
Length = 45
Area of Vegetable Garden = 20×45=900 Sq ft

Area of Entire Garden = Width × Length
Width = 20 + 2x
Length = 45 + 2x
Area = (20 + 2x)(45 + 2x)
(2x + 20)(2x + 45)
4x^2 + 90x + 45x + 900
Area of Entire Garden = 4x^2 + 135x + 900

Area of Flower Garden = Area of Entire Garden - Area of Vegetable Garden

(4x^2 + 135x + 900) - (20 × 45)
4x^2 + 135x + 900 - 900
Area of Flower Garden = 4x^2 + 135x

7 0
3 years ago
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