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Yakvenalex [24]

2 years ago

13

37 is 60% of what number?

1 answer:

liubo4ka [24]2 years ago

6 0

Answer:

61 2/3 = n

Step-by-step explanation:

Is means equals and of means multiply

37 = 60% * n

37 = .60n

divide each side by .60

37 / .60 = .60n/.60

61.6666666 repeating = n

61 2/3 = n

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maks197457 [2]

<u>10M </u><u>different </u><u>codes </u><u>are possible.</u>

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Probability is a measure of the likelihood of an event to occur. Many events cannot be predicted with total certainty. We can predict only the chance of an event to occur i.e. how likely they are to happen, using it.
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It’s simple. there are 7 digits, so that would mean you start with 0,000,000 and end with 9,999,999.
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1 year ago

The values in the table represent a function.

Hatshy [7]

Given:

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x f(x)

-2 1

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4 -2

-3 0

0 4

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Function notation for the ordered pair given in the first row in the table.

Solution:

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6 0

2 years ago

Read 2 more answers

What is the answer to 15/4 + (-41/3)

Tom [10]

use the app called "photo math" will give you your answers i would but the pic is too blurry

5 0

2 years ago

A central angle, thata, of a circle with radius 16 inches intercepts an arc of 19.36 inches. Find thata.

kaheart [24]

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5 0

3 years ago

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if the recommended daily allowance for vitamin c is 60 mg per day and there are 70 mg of vitamin C per 100 g orange, how many 3.

noname [10]

Answer: 7

Step-by-step explanation:

Given : The recommended daily allowance for vitamin c is 60 mg per day .

Then, for one whole week , the recommended allowance for vitamin c will be :-

$7\times60=420\text{ mg}$

Also, there are 70 mg of vitamin C per 100 g orange.

1 g = 1000 ml

The proportion of Vitamin C in 100 g = $\dfrac{70}{100000}=0.0007$

1 oz =28.3495 grams

Then, $3\ oz= 3\times28.3495=85.0485 \text{ gm}=85048.5\ mg$

Then, amount of vitamin C in 85048.5 mg = $0.0007\times85048.5=59.53395\approx59.53\ mg$

Then, the number of oranges have to eat each week to meet this requirement= $\dfrac{420}{59.53}\approx7$

Hence, about 7 oranges you would have to eat each week to meet this requirement.

8 0

3 years ago