5 cause u get more apples for 2.35 and still save money but get what u need
The probability that a plant in the experiment receives visible or ultraviolet light is 7/10.
<u>Step-by-step explanation</u>:
The total number of plants in the experiment = 30 plants
Plants that receive visible light alone = 12 plants
Plants that receive ultraviolet light alone = 15 plants
Plants that receive both visible and ultraviolet light = 6 plants
<u>step 1</u> :
<em>Probability = No. of required events / Total number</em>
<u>step 2</u> :
P(visible) = 12 / 30
P(ultraviolet) = 15 / 30
P(both) = 6 / 30
<u>step 3</u> :
P(visible or ultraviolet) = P(visible) + P(ultraviolet) - P(both)
= 12/30 + 15/30 - 6/30
= 21/30
P(visible or ultraviolet) = 7/10
<span>In a 30-60-90 triangle the side opposite the 30 degree angle is half the length of the hypotenuse.
The shorter leg is </span>the side opposite the 30 degree angle, therefore
the shorter leg = 30/2 = 15
<span>By the Pythagorean theorem
</span><span>the longer leg = </span>√(30² - 15²) = √(900-225) = √675 = 15√3 ≈ 25.98 units
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
