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2 years ago

How many solutions does this equation have?

Mathematics

1 answer:

Greeley [361]2 years ago

4 0

Answer:

No solution

Explanation:

-4+19-7f = -15-7

cancel terms on both sides ( add 7f on both sides)

Calculate the sum

-4+19= -15

-4+19=15

15 = -15

The statement 15 = -15 is false so there is no solution :)

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Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.

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x = no. of times owner-occupied units had a water supply stoppage.

<h3>What is the probability at x =0?</h3>

P(x=0) = 547000/14770000

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Similarly, we have at x=1

P(x=1) = 5012000/14770000

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P(x=2) = 6110000/14770000

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P(x=3) = 2544000/14770000

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P(x=4) = 557000/14770000

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x f(x)

0 0.0370

1 0.3393

2 0.4137

3 0.1722

4 0.0378

Total 1

Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.

To learn more about the probability distribution visit:

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3 years ago

The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.3 days and a standard de

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Answer:

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

Step-by-step explanation:

Step(i):-

Given mean of the Population μ = 5.3 days

Given standard deviation of the population 'σ' = 2 days

Let 'X' be the random variable in normal distribution

Let x₁ = 4

$Z_{1} = \frac{x_{1}-mean }{S.D} = \frac{4-5.3}{2} = -0.65$

Let x₂ = 7

$Z_{2} = \frac{x_{2}-mean }{S.D} = \frac{7-5.3}{2} = 0.85$

Step(ii):-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = P(-0.65≤Z≤0.85)

= P(Z≤0.85) - P(Z≤-0.65)

= 0.5 + A( 0.85) - ( 0.5 - A(-0.65)

= 0.5 + A( 0.85) - 0.5 +A(0.65) ( ∵A(-0.65) = A(0.65)

= A(0.85) + A(0.65)

= 0.3023 + 0.2422

= 0.5445

Final answer:-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

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