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Anika [276]
3 years ago
5

Raj builds a side table in the shape of a cube. Each edge of the cube measures 20 inches. Raj wants to cover the top and four si

des of the table with ceramic tiles. Each tile has an edge length of 4 inches. How many tiles will he need?

Mathematics
1 answer:
Mumz [18]3 years ago
3 0

Answer:

Step-by-step explanation:

20in * 20in = 400in sq

400in sq * 5 sides = 2,000in sq needed.

4in * 4in = 16in sq

Take the 2,000in sq needed and divid it by the 16in each tile covers.

2,000 / 16 = 125 tiles

Therefore, you would need 125 tiles to cover 5 sides of the table.  Top and four sides.

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The floor of a conference hall can be covered completly with tiles.Its length is 36ft. longer than its width.The area of the flo
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Answer:

Step-by-step explanation:

Given

Area of a floor = 2040ft²

If Its length is 36ft. longer than its width, then L = W+36

Area = LW

L is the length

W is the width

A <  W(W+36)

2040 < W²+36W

0<W²+36W-2040

W²+36W-2040 >0

W = -36±√36²-4(-2040)/2

W =  -36±√1296+8160)/2

W =  -36±√9456/2

W =  -36±97.25/2

W = -36+97.25/2

W = 61.24/2

W > 30.62ft

Since L = W+36

L > 30.62+36

L > 66.62ft

The width of the floor is 30.62ft

The length is 66.62ft

The mathematical sentence would represent the given situation is the width is greater than 30.62ft while the length must be greater than 66.62ft

The possible dimension of the floor is 31ft by 67 ft

The possible areas is 31*67 = 2077ft²

It won't be realistic to get an area of 144sqft because the initial area is greater than 144. Hence the feasible area will be greater than 2040ft²

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3 years ago
What is the total of 1500 with 5% sales tax
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