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3 years ago

Did I do this right ? If not then how is it supposed to be solved ?

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

6 0

Yeah, you got it right, and that's how you're supposed to do it (if you're supposed to round sqrt(17))! Great job!

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Which expression is equivalent to 15 (n+3/n) ? £ N=10

Alika [10]

Answer:

$\sum_{n=10}^{15}(n+\frac{3}{n})=\sum_{n=10}^{15} n + \sum_{n=10}^{15} \frac{3}{n}$

Step-by-step explanation:

Given expression : $\sum_{n=10}^{15}(n+\frac{3}{n})$

Solving further:

$\sum_{n=10}^{15}(n+\frac{3}{n})$

$\Rightarrow \sum_{n=10}^{15} n + \sum_{n=10}^{15} \frac{3}{n}$

So, $\sum_{n=10}^{15}(n+\frac{3}{n})=\sum_{n=10}^{15} n + \sum_{n=10}^{15} \frac{3}{n}$

So, Option A is true

Hence the given expression is equivalent to Option A

6 0

3 years ago

If 9 (x) = – 5x2 – 4x + 19 find f (–3)

Sliva [168]

Answer:

- 14

Step-by-step explanation:

$f(x) = - 5 {x}^{2} - 4x + 19 \\ plug \: x = - 3 \\ f( - 3) = - 5 {( - 3)}^{2} - 4( - 3) + 19 \\ f( - 3) = - 5 \times 9 + 12 + 19 \\ f( - 3) = - 45 + 31 \\ f( - 3) = -14$

7 0

3 years ago

The sides of an equilateral triangle measure 16 inches. The midpoints of the sides of the triangle are joined to form another eq

Rina8888 [55]

The perimeter of all four triangles is: 90 inches.

7 0

4 years ago

Read 2 more answers

Find the equation of a circle that has a diameter with the endpoints given by the points A(-4,9) and B (- 2, - 3) )

Aleksandr-060686 [28]

The equation of the circle is $(x+3)^{2}+(y-3)^{2}=37$

Explanation:

Given that the endpoints of the circle are A(-4,9) and B(-2,-3)

We need to determine the equation of the circle.

Center:

The center of the circle can be determined using the midpoint formula,

$Center=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Substituting the coordinates A(-4,9) and B(-2,-3), we get,

$Center=(\frac{-4-2}{2},\frac{9-3}{2})$

$Center=(\frac{-6}{2},\frac{6}{2})$

$Center=(-3,3)$

Thus, the center of the circle is (-3,3)

Radius:

The radius of the circle can be determined using the distance formula,

$r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Substituting the center (-3,3) and the endpoint (-4,9), we get,

$r=\sqrt{\left(-4+3\right)^{2}+\left(9-3\right)^{2}}$

$r=\sqrt{\left(-1\right)^{2}+\left(6\right)^{2}}$

$r=\sqrt{1+36}$

$r=\sqrt{37}$

Thus, the radius of the circle is $\sqrt{37}$

Equation of the circle:

The standard form of the equation of the circle is given by

$(x-a)^{2}+(y-b)^{2}=r^{2}$

where (a,b) is the center and r is the radius.

Substituting the values, we have,

$(x+3)^{2}+(y-3)^{2}=(\sqrt{37})^{2}$

$(x+3)^{2}+(y-3)^{2}=37$

Thus, the equation of the circle is $(x+3)^{2}+(y-3)^{2}=37$

7 0

3 years ago

100 points

Andru [333]

Just a little note you put 50 points and not 100

The y-axis doesn't start at zero.

The intervals on the y-axis are too large.

Different bar widths are used on the same graph.

The y-axis starts at zero but has different intervals.

6 0

3 years ago

Read 2 more answers