1
P(V|A) is not 0.95. It is opposite:
P(A|V)=0.95
From the text we can also conclude, that
P(A|∼V)=0.1
P(B|V)=0.9
P(B|∼V)=0.05
P(V)=0.01
P(∼V)=0.99
What you need to calculate and compare is P(V|A) and P(V|B)
P(V∩A)=P(A)⋅P(V|A)⇒P(V|A)=P(V∩A)P(A)
P(V∩A) means, that Joe has a virus and it is detected, so
P(V∩A)=P(V)⋅P(A|V)=0.01⋅0.95=0.0095
P(A) is sum of two options: "Joe has virus and it is detected" and "Joe has no virus, but it was mistakenly detected", therefore:
P(A)=P(V)⋅P(A|V)+P(∼V)⋅P(A|∼V)=0.01⋅0.95+0.99⋅0.1=0.1085
Answer:
Step-by-step explanation:
Let the price for children and adults package be represented with x and y respectively.
For the first week the sum of the package will be as follows:
3x+8y = 126
For the two weeks after:
6x+4y= 108
So, we will be having two equations
3x+8y = 126..... (1)
6x+4y= 108.......(2)
These are simultaneous equations
From equation 1
3x+8y = 126
3x = 126-8y
X = 126-8y/3 ............. (3)
Put equation 3 into 2
6 ( 126-8y)/3 +4y = 108
756-48y/3 +4y = 108
756-48y+12y/3 = 108
Cross multiplying
756-48y+12y= 108×3
756-48y+ 12y = 324
Collecting like terms
756-324 = 48y-12y
432= 36y
Divide both sides by 36
432/36 = 36y/36
y= 12
Substituting y into equation 1
3x+8= 126
3x+96=126
3x= 126-96
3x= 30
Divide both sides by 3
3x/3 = 30/3
x = 10
Hence for each of the packages for children and adults. It will be 10 and 12 respectively.
Answer:
First ones 90 and the second one is 48
Step-by-step explanation:
please brainliest me
27-48x^4= 3(9-16x^4)
Because 3 is the GCF
