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2 years ago

jerry's softball team is made up of 15 players,and 9 of them are boys.On the team,what is ratios to boys to girls?

Mathematics

1 answer:

weqwewe [10]2 years ago

3 0

Answer:

9:6

Step-by-step explanation:

boys= 9 teammates

girls= 6 teammates

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-5 + a =21 what’s A?

KonstantinChe [14]

Answer:

A=21+5

A=26

Step-by-step explanation:

just shift 5 to right side

3 0

3 years ago

SIMPLIFY (x + 5)(2x - 6) A) 2x2 - 30 B) 2x2 - 6x C) 2x2 + 7x - 6 D) 2x2 + 4x - 30

alina1380 [7]

Answer:

D) 2x²+4x-30

Step-by-step explanation:

You would multiply x and 2x; x and -6; 5 and 2x; 5 and -6

(x)(2x) = 2x²

(x)(-6) = -6x

(5)(2x) = 10x

(5)(-6) = -30

Now just put it back in the order that it was listed in the equation starting with (x)(2x)

This would give you 2x²-6x+10x-30

Simplify even further to get 2x²+4x-30

4 0

3 years ago

Read 2 more answers

Retion number are numbers that can be written as fraction or_____

Rudik [331]

Answer: integer

Step-by-step explanation:

3 0

3 years ago

Henry bought 2 kilograms of chicken for a family dinner. After, only 61.5 grams were left. How much chicken was eaten, in kilogr

ASHA 777 [7]

He still has 1938.5 kilograms of chicken left. Hope it helped.

5 0

3 years ago

Read 2 more answers

Use variation of parameters to find a general solution to the differential equation given that the functions y1 and y2 are linea

Aleks [24]

Recall that variation of parameters is used to solve second-order ODEs of the form

y''(t) + p(t) y'(t) + q(t) y(t) = f(t)

so the first thing you need to do is divide both sides of your equation by t :

y'' + (2t - 1)/t y' - 2/t y = 7t

You're looking for a solution of the form

$y=y_1u_1+y_2u_2$

where

$u_1(t)=\displaystyle-\int\frac{y_2(t)f(t)}{W(y_1,y_2)}\,\mathrm dt$

$u_2(t)=\displaystyle\int\frac{y_1(t)f(t)}{W(y_1,y_2)}\,\mathrm dt$

and W denotes the Wronskian determinant.

Compute the Wronskian:

$W(y_1,y_2) = W\left(2t-1,e^{-2t}\right) = \begin{vmatrix}2t-1&e^{-2t}\\2&-2e^{-2t}\end{vmatrix} = -4te^{-2t}$

Then

$u_1=\displaystyle-\int\frac{7te^{-2t}}{-4te^{-2t}}\,\mathrm dt=\frac74\int\mathrm dt = \frac74t$

$u_2=\displaystyle\int\frac{7t(2t-1)}{-4te^{-2t}}\,\mathrm dt=-\frac74\int(2t-1)e^{2t}\,\mathrm dt=-\frac74(t-1)e^{2t}$

The general solution to the ODE is

$y = C_1(2t-1) + C_2e^{-2t} + \dfrac74t(2t-1) - \dfrac74(t-1)e^{2t}e^{-2t}$

which simplifies somewhat to

$\boxed{y = C_1(2t-1) + C_2e^{-2t} + \dfrac74(2t^2-2t+1)}$

4 0

3 years ago