Step-by-step explanation:
This time round, use SOH method (Sin angle = Opposite/Hypotenuse)
given Opposite = 7
Hypotenuse = 10
Answer:
a)6
b)v^2-u^2/2a
Step-by-step explanation:
a)Given that,
u=12
a= -6
s=9
We know that,
v^2=u^2+2as
or, v^2=(12)^2+2×(-6)×9
or,v^2=144-108
or,v^2=36
or, v=√36
∴v=6
(Ans)
b)If ,v^2=u^2+2as
then, u^2+2as=v^2
or,2as=v^2-u^2
or, s=v^2-u^2/2a
∴s=v^2-u^2/2a
Hope ya find it helpful.. Thanks a lot...
It is not a circle but you can find the equation of the ellipse.
To do this we need to work out the major and minor radii and the centre
The centre is at (9, 7)
The major (y) radius is 1 and the minor (x) radius is 5
Therefore the equation is (x-9)/5 + (y-7)/1 = 1
Answer:
806.12 m
Step-by-step explanation:
<u>Step 1: Write the data</u>
<em>Side (s) = 12</em>
<em>Altitude (h) = 6</em>
<u>Step 2: Write the formula for surface area of right hexagonal pyramid</u>
<em>Area = 3√3/2*s² + 3*s*√(h²+3s²/4)</em>
<u>Step 3: Substitute values of 's' and 'h'</u>
<em>Area = 3√3/2*(12)² + 3*(12)*√[6²+3(12)²/4]</em>
Area = 806.12 m
Therefore, the total surface area of the pyramid is 806.12 m.
!!
