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2 years ago

Someone help!!! What is 4/5+7/8

Mathematics

2 answers:

noname [10]2 years ago

5 0

Im pretty sure the answer is 1.675

Arisa [49]2 years ago

5 0

1.675 or 1 27/40 ...............

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Write an equation in<br> y = mx + b form for<br> the line graphed.

Dimas [21]

Answer:

y=2x-5

explanation

m is gradient so rise over run and b is the y intercept which is -5

7 0

2 years ago

Read 2 more answers

A necklace has and matching bracelet have two types of beads. The necklace has 12 large beads and 8 small beads and weighs 88 gr

miv72 [106K]

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Step-by-step explanation:

Let,

Weight of one large bead = x

Weight of one small bead = y

According to given statement;

12x+8y=88 Eqn 1

5x+2y=25 Eqn 2

Multiplying Eqn 2 by 4

$4(5x+2y=25)\\20x+8y=100\ \ \ Eqn\ 3\\$

Subtracting Eqn 1 from Eqn 3

$(20x+8y)-(12x+8y)=100-88\\20x+8y-12x-8y=12\\8x=12$

Dividing both sides by 8

$\frac{8x}{8}=\frac{12}{8}\\x=1.5$

Putting x=1.5 in Eqn 1

$12(1.5)+8y=88\\18+8y=88\\8y=88-18\\8y=70$

Dividing both sides by 8

$\frac{8y}{8}=\frac{70}{8}\\y=8.75$

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

5 0

2 years ago

A Web music store offers two versions of a popular song. The size of the standard version is

kicyunya [14]

2.4x+4.7(4x)=5936
Solve for x
X=280 standard version

4×280=1,120 high-quality version

5 0

3 years ago

What is the constant term in (2x+9)(x-4)(x+5)

andrezito [222]

Answer:

$-180$

Step-by-step explanation:

$\left(2x+9\right)\left(x-4\right)\left(x+5\right)$

$\left(2x^2+x-36\right)\left(x+5\right)$

$2x^3+11x^2-31x-180$

6 0

2 years ago

Read 2 more answers

Can someone please help me.

skelet666 [1.2K]

To find the slope of the line, you need two points.
(-2 , 5) and (3 , -5)

5 - (-5) / -2 - 3
10 / -5 = -2

The slope of the line is -2. So your answer is C.

8 0

2 years ago