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fenix001 [56]
3 years ago
14

2X +7 < 3X -5——————————————————————————————-

Mathematics
2 answers:
Andrew [12]3 years ago
7 0

Answer:

x=12

Step-by-step explanation:

2x+7=3x-5

2x=3x-5-7

2x=3x-12

2x-3x=-12

-x=-12

x=12

or

2x+7=0

2x=-7

x=-3.5

3x-5=0

3x=5

x=1.6

-3.5<1.6

mr Goodwill [35]3 years ago
6 0

Answer:

x>12

Step-by-step explanation:

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6.<br> A. y=-13x1<br> or B. y = 1-3xl
IrinaVladis [17]

Answer: B

Step-by-step explanation

6 0
3 years ago
If x = -6,which inequiality is true
zimovet [89]

The only equation that works with x=-6 is A

7 0
3 years ago
Factor using the trinomial<br> 10.<br> X2 + 13x + 12
Rudik [331]

Answer:

Factoring the trinomial: x^2+13x+12 we get the factors \mathbf{(x+1)(x+12)}

Step-by-step explanation:

We need to factor the trinomial: x^2+13x+12

We can factor the trinomial by breaking the middle term i.e 13x

Such that adding or subtracting gets the both terms we get 13x and multiplying both terms we get 12x^2

We can break 13x as: 12x and x

Adding them we get 13x and multiplying them we get 12x^2

So,

x^2+13x+12\\=x^2+12x+x+12\\=x(x+12)+1(x+12)\\=(x+1)(x+12)

So, Factoring the trinomial: x^2+13x+12 we get the factors \mathbf{(x+1)(x+12)}

8 0
3 years ago
please help now it kinda important i get it done soon or i cant go to a dance for my school tomorrow. im begging u ill give u 5
harkovskaia [24]

Answer: 352496

Step-by-step explanation:

First, to find 20% of 440,620, you can multiply:

0.2 x 440,620 = 88,124

Then, to find the new weight of the ship, you can subtract the 20% that was just found (88,124) from the ship's original weight (440,620) to get:

440,620 - 88,124 = 352,496

Therefore, the ship's weight is now 352496.

I hope this helps!

6 0
2 years ago
Lim t^4 - 6 / 2t^2 - 3t + 7
Harman [31]

I think you meant to say

\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}

(as opposed to <em>x</em> approaching 2)

Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}

6 0
3 years ago
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