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anastassius [24]
3 years ago
10

Craig won first prize in Mrs. Short's class

Mathematics
2 answers:
NemiM [27]3 years ago
7 0

Answer:

1/7

Step-by-step explanation:

there is seen prizes and he pulls seven times so the odds would be 1/7

Rufina [12.5K]3 years ago
5 0

Answer:

\frac{1}{7}

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Round $56.29 to the nearest dollar.
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$56

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HELP!!!Find the complex number (a+bi) that when added to (4-2i) equals (-2+12i)
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Without graphing, determind whether the function represents exponential growth or exponential decay then find the y intercept
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Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy
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Answer:

H 0 : μ = 3.1    H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66

df = n-1=75-1 =74

The p value is:

p_v = P(t_{74} >8.66) =3.65x10^{-13}

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1    H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

\bar X = 3.13 , s =0.03 , n =75

The statistic to check the hypothesis is given by:

t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}

Replacing the info given we got:

t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66

The degrees of freedom are given by:

df = n-1=75-1 =74

The p value since is a right tailed ted is given by:

p_v = P(t_{74} >8.66) =3.65x10^{-13}

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

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3 years ago
Analyze Ben’s work. Did he simplify the expression correctly? If not, what was his mistake?
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Answer: No, he needed to apply the exponent to all factors in the product in the second step.

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