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DochEvi [55]
3 years ago
7

A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=72t-16t^2. After how l

ong will it reach its maximum height?
Mathematics
2 answers:
Dahasolnce [82]3 years ago
8 0

Answer:

<h2>h(x) = 72t - 16t^2 h in feet - t in seconds</h2><h2 /><h2>This is a formula that models the velocity of a thrown ball.</h2><h2 /><h2 /><h2 /><h2>When the ball has reached the maximum height acceleration is 0.</h2><h2 /><h2 /><h2 /><h2>The formula for the acceleration for this equation is the derivative of the original equation.</h2><h2 /><h2>This equation is 72 - 32t.</h2><h2 /><h2>Set the equation to 0.</h2><h2 /><h2 /><h2 /><h2>0 = 72 - 32t t in seconds</h2><h2 /><h2 /><h2 /><h2>32t = 72</h2><h2 /><h2>t = 2.25 seconds.</h2><h2 /><h2 /><h2 /><h2>Subtitute 2.25 into the original equation.</h2><h2 /><h2>72(2.25) - 16(2.25^2) = h in feet</h2><h2 /><h2>162 - 16(5.0625) = h in feet</h2><h2 /><h2>162 - 81 = h in feet</h2><h2 /><h2>81 feet = h</h2>

Step-by-step explanation:

<u>#CARRY</u><u> </u><u>ON</u><u> </u><u>LEARNING</u><u> </u>

galben [10]3 years ago
4 0

Answer:

i coulnt answer this i love you

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