A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=72t-16t^2. After how l

Question

DochEvi [55]

2 years ago

7

A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=72t-16t^2. After how l

ong will it reach its maximum height?

Mathematics

2 answers:

Dahasolnce [82] · Answer 1 · 2022-09-02T12:08:48+03:00

Answer:

<h2>h(x) = 72t - 16t^2 h in feet - t in seconds</h2><h2 /><h2>This is a formula that models the velocity of a thrown ball.</h2><h2 /><h2 /><h2 /><h2>When the ball has reached the maximum height acceleration is 0.</h2><h2 /><h2 /><h2 /><h2>The formula for the acceleration for this equation is the derivative of the original equation.</h2><h2 /><h2>This equation is 72 - 32t.</h2><h2 /><h2>Set the equation to 0.</h2><h2 /><h2 /><h2 /><h2>0 = 72 - 32t t in seconds</h2><h2 /><h2 /><h2 /><h2>32t = 72</h2><h2 /><h2>t = 2.25 seconds.</h2><h2 /><h2 /><h2 /><h2>Subtitute 2.25 into the original equation.</h2><h2 /><h2>72(2.25) - 16(2.25^2) = h in feet</h2><h2 /><h2>162 - 16(5.0625) = h in feet</h2><h2 /><h2>162 - 81 = h in feet</h2><h2 /><h2>81 feet = h</h2>

Step-by-step explanation:

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galben [10] · Answer 2 · 2022-09-02T11:03:36+03:00

galben [10]2 years ago

4 0

Answer:

i coulnt answer this i love you