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balu736 [363]
3 years ago
14

Please help me to solve this​

Mathematics
1 answer:
zzz [600]3 years ago
3 0

Answer:

Below in bold.

Step-by-step explanation:

First find the height by use Pythagoras theorem on the right triangle:

h = sqrt (5^2 - 4^2)

= sqrt 9

= 3.

Volume of the prism = area of the triangle * length

= 1/2 * 3 * 4 * 10

= 1/2 * 12 * 10

= 60 cm^3.

Total area = area of 2 triangles + area 0f 3 rectangles

= 2 * 1/2 * 3 * 4 + 3 * 10 +  4 * 10 + 5 * 10

= 12 + 30 + 40 + 50

= 132 cm^2.

You might be interested in
Two points are _______________________ collinear
kramer

Answer:

a

Step-by-step explanation:

Two points are always collinear since we can draw a distinct (one) line through them.

6 0
3 years ago
Two systems of equations are shown below:
Sati [7]
System A:
6x + y = 2
-x - y = -3

System B:
2x - 3y = -10
-x-y = -3

Solve:
System A:
6x + y = 2
y = 2 - 6x
-x - (2-6x) = -3
-x - 2 + 6x = -3
5x = -3 + 2
5x = -1
x = -1/5
y = 2 - 6(-1/5)
y = 2 + 6/5
y = 2 + 1.2
y = 3.2     System A: x = -1/5 or -0.2  ; y = 3 1/5 or 3.2

System B:
2x - 3y = -10
2x = -10 + 3y
x = -5 + 1.5y
-x - y = -3
-(-5 + 1.5y) -y = -3
5 - 1.5y - y = -3
-2.5y = -3 - 5
-2.5y = -8
y = 3.2
x = -5 + 1.5(3.2)
x = -5 + 4.8
x = -0.2   System B: x = -0.2 ; y = 3.2

<span>B) They will have the same solution because the first equations of both the systems have the same graph.</span>

6 0
3 years ago
Read 2 more answers
The junior senator can do a labyrinth in 50 minutes. The senior senator can do a labyrinth in 30 minutes. Working together, how
vladimir2022 [97]

Answer:

225\:\text{minutes}

Step-by-step explanation:

To navigate through this problem, start by finding how much each senator can complete in a fixed amount of time. I'll choose 10 as it's the greatest common factor of 30 and 50.

In 10 minutes, the junior senator can complete \frac{10}{50}=\frac{1}{5} of the labyrinth.

In 10 minutes, the senior senator can complete \frac{10}{30}=\frac{1}{3} of the labyrinth.

Therefore, working together, they can complete \frac{1}{5}+\frac{1}{3}=\frac{8}{15} of the labyrinth in 10 minutes. Thus, it will take them \frac{15}{8}\cdot 10 \text{ minutes}=18.75\:\text{minutes} to complete one labyrinth.

The amount of time it take them to complete 12 labyrinths is then 18.75\cdot 12 =\boxed{225\:\text{minutes}}

5 0
2 years ago
You purchase 26 parking hours that you can use the next month to park your food truck at the fair. Weekday hours park $2 per hou
ICE Princess25 [194]

Answer:

Number of week day hours purchased  is 5

Step-by-step explanation:

Total number of Parking hours purchased = 26 parking hours

Parking cost on weekdays = $2 per hour

Parking costs on weekends = $10 per hour

Total amount spent on parking =  $220.

To Find:

Number of week days purchased = ?

Solution:

Let  

The number of week days purchased be x

The number of weekends purchased be  y

We know that the total hours purchased is 26

So,

x+y = 26

y = 26-x------------------------------------------------------(1)

Now the total cost is 220

(Total number of weekdays X cost per weekday ) +(Total number of weekends + cost per weekend) =220

Substituting the values

=>x\times 2 + y \times 10 = 220

=>x \times 2 + (26-x) \times 10 =220

=>2x + 260 -10x =220

=>260 -8x = 220

=>260 -220 =8x

=>40 = 8x

=>x=\frac{40}{8}

x= 5-------------------------------------------(2)

Now substituting (2) in (1) we get

y= 26-5

y= 21

7 0
3 years ago
Let X denote the data transfer time (ms) in a grid computing system (the time required for data transfer) between a "worker" com
My name is Ann [436]

Answer:

a. The value of alpha is 3.014 and the value of beta is 12.442

b. The probability that data transfer time exceeds 50ms is 0.238

c. The probability that data transfer time is between 50 and 75 ms is 0.176

Step-by-step explanation:

a. According to the given data we have that the mean and standard deviation of the random variable X are 37.5 ms and 21.6.

Therefore, E(X)=37.5 and V(X)=(21.6)∧2  

To calculate alpha we would have to use the following formula:

alpha=E(X)∧2/V(X)

alpha=(37.5)∧2/21.6∧2

alpha=1,406.25 /466.56

​alpha=3.014

To calculate beta we would have to use the following formula:

β=  V(X) ∧2/E(X)

β=(21.6)  ∧2/37.5

β=466.56 /37.5

β=12.442

b. E(X)=37.5 and V(X)=(21.6)∧2  

Therefore, P(X>50)=1−P(X≤50)

Hence, To calculate the probability that data transfer time exceeds 50ms we use the following formula:

P(X>50)=1−P(X≤50)

=1−0.762

=0.238

The probability that data transfer time exceeds 50ms is 0.238

c. E(X)=37.5 and V(X)=(21.6)∧2  

​Therefore, P(50<X<75)=P(X<75)−P(X<50)  

Hence, To calculate the probability that data transfer time is between 50 and 75 ms we use the following formula:

P(50<X<75)=P(X<75)−P(X<50)

=0.938−0.762

=0.176

​

The probability that data transfer time is between 50 and 75 ms is 0.176

6 0
3 years ago
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