Are the two triangles similar? how do you know?
1 answer:
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Answer: The area of the parallelogram is:
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in² = 1174 ⅛ in² = 1174.125 in² .
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Explanation:
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Area of a parallelogram:
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A = base * height = b * h ;
From the figure (from the actual "question"):
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b = 50.5 in.
h = 23.25 in.
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Method 1) A = b * h =
= (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as: 1174 <span>⅛ .
</span>____________________________________________________________
Method 2) A = b * h =
= (50 ½ in) * (23 <span>¼ in) =
= (</span>
in) * (
<span> in) ;
</span>___________________________________________________________
Note: "50 ½ " = [(50*2) + 1 ] / 2 = ;
Note: "23 ¼ " = [(23*4) + 1 ] / 4 = ;
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→ A = ( in) * ( in) ;
→ A =
in² = in² ;
→ A = (9393/8) in² =
→ A = in² = 1174 ⅛ in² = 1174.125 in² .
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_______________________________________________________
_______________________________________________________
Explanation:
_______________________________________________________
Area of a parallelogram:
_______________________________________________________
A = base * height = b * h ;
From the figure (from the actual "question"):
_______________________________________
b = 50.5 in.
h = 23.25 in.
____________________________________________________________
Method 1) A = b * h =
= (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as: 1174 <span>⅛ .
</span>____________________________________________________________
Method 2) A = b * h =
= (50 ½ in) * (23 <span>¼ in) =
= (</span>
</span>___________________________________________________________
Note: "50 ½ " = [(50*2) + 1 ] / 2 =
Note: "23 ¼ " = [(23*4) + 1 ] / 4 =
____________________________________________________________
→ A = (
→ A =
→ A = (9393/8) in² =
→ A =
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