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3 years ago

HELP PLEASE : For numbers 3 & 4, draw a triangle for each to find the missing side.

Mathematics

2 answers:

Virty [35]3 years ago

7 0

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Answer: 1) b = 2

2) c = 20

Explanation:

I hope this helped!

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Dahasolnce [82]3 years ago

6 0

Answer:

3) b = 2.24

4) c = 15.62

Step-by-step explanation:

Pythagorean formula:

a² + b² = c²

2² + b² = 3²

4 + b² = 9

b² = 5

b = 2.24

a² + b² = c²

10² + 12² = c²

100 + 144 = c²

244 = c²

c = 15.62

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If g(x) is a linear function such that g(-3) = 2 and g(1) = -4, find g(7).

eimsori [14]

<h3>Answer: -13</h3>

=======================================

Explanation:

g(-3) = 2 means x = -3 and y = 2 pair up together to form the point (-3,2)

g(1) = -4 means we have the point (1,-4)

Find the slope of the line through the two points (-3,2) and (1,-4)

m = (y2-y1)/(x2-x1)

m = (-4-2)/(1-(-3))

m = (-4-2)/(1+3)

m = -6/4

m = -3/2

m = -1.5

The general slope intercept form y = mx+b turns into y = -1.5x+b after replacing m with -1.5

Plug in (x,y) = (-3,2) which is one of the points mentioned earlier and we end up with this new equation: 2 = -1.5*(-3) + b

Let's solve for b

2 = -1.5*(-3)+b

2 = 4.5 + b

2-4.5 = 4.5+b-4.5 .... subtract 4.5 from both sides

-2.5 = b

b = -2.5

Therefore, y = mx+b becomes y = -1.5x-2.5 meaning the g(x) function is g(x) = -1.5x-2.5

The last step is to plug in x = 7 and compute

g(x) = -1.5*x - 2.5

g(7) = -1.5*7 - 2.5

g(7) = -10.5 - 2.5

g(7) = -13

6 0

3 years ago

Read 2 more answers

What is (x2 + 7x + 6) divided by (x + 1)? A) x - 6 B) x - 7 C) x + 6 D) x + 7

Nana76 [90]

So the ans is C. 

hope this will help u...

7 0

3 years ago

Read 2 more answers

PLSSS HELP IF YOU TURLY KNOW THISS

dmitriy555 [2]

Answer:

Step-by-step explanation:

to change a mixed number into an improper fraction

a $\frac{b}{c}$ = $\frac{ac+b}{c}$ , then

9 $\frac{1}{3}$

= $\frac{9(3)+1}{3}$

= $\frac{27+1}{3}$

= $\frac{28}{3}$

7 0

2 years ago

Read 2 more answers

How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the

miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

$\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}$

___

$\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}$

___

$\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}$

Neither solution makes any denominator be zero, so both are good solutions.

8 0

3 years ago

This question is confusing me

Ksenya-84 [330]

It’s C that’s the only one that works

6 0

3 years ago