Outline the process for inscribing a square in a circle. Perform the construction in GeoGebra, and take a screenshot of the cons
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Diagonal of the parallelogram divides the parallelogram in to two equal areas.
So area of parallelogram = 2(area of triangle)
According to the given diagram,
AB= 8, AD = 5 and BD = 11
So according to the Heron's formula,
Area of triangle =
and a, b and c are the three sides of the triangle
Area of triangle ABD =
So, area of parallelogram ABCD = 2(area of triangle ABD)
area of parallelogram ABCD = 2 (18.33)
area of parallelogram ABCD = 36.66
area of parallelogram ABCD = 36.7 sq. units
