Answer:
-13x+10
Step-by-step explanation:
(4x+5)(x-2)
Multiply each term in the first parenthesis by each term in the second (foil)
Step 1: Expand it by writing out each multiplication. I added a picture showing which order to do it. (go in order of green, red, blue, yellow.) (you can remember this as first, outside, inside, last.)
When you expand it'll look like: 4x⋅x+4x⋅-2-5x-5⋅-2
Step 2: Calculate product
4x⋅x+4x⋅-2-5x-5⋅-2 (for the 4x⋅x it would be written like )
+4x⋅-2-5x-5⋅-2
+4x⋅-2-5x-5⋅-2 (4x⋅-2 becomes -8x) (multiply 4x times -2)
-8x-5x-5⋅-2
-8x-5x-5⋅-2 (-5⋅-2 becomes +10) (multiply -5 times -2)
-8x-5x+10
Step 3: collect like terms
-8x-5x+10 (-8x-5x becomes -13x) (-8x times -5x)
-13x+10 is the most simplified so it should be your final answer
Answer: 49°, 49°, 82°
<u>Step-by-step explanation:</u>
Let x represent the base angles
then 2x - 16 is the vertex angle.
Triangle Sum Theorem states that the sum of the angles is 180°
(x) + (x) + (2x - 16) = 180
4x - 16 = 180
4x = 196
x = 49
Base angles: x = 49
Vertex angle: 2(49) - 16 = 82
Answer:
3x-22=80+x
3x-x=80+22
2x=102
x=51
Step-by-step explanation:
the exterior angle is (3x-22) and then is equal to sum of 80 and x
and then we get 51
Answer:
Step-by-step explanation:
(3m-1)(6-a)-(m+3)(6-a)
=3m(6-a)-1(6-a)-m(6-a)+3(6-a)
=18m-3ma-6+a-6m+ma+18-3a
=12m-2ma+12-2a
=2(6m-ma+6-a)
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
