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Softa [21]
3 years ago
8

Look Ahead Grace's original rug has a length of 2 yards and a width of yard. You can write the ratio of length to width as 2 : 3

. To find the unit rate, you can start with the complex fraction ? Fractions in which the numerator, the denominator, or both are also fractions are called complex fractions. 2 a. You can simplify a complex fraction by dividing. Since a fraction bar represents division, you can think of as 2 . Then you can divide to simplify. What is the unit rate for the length to width of Grace's rug? 3 b. Rewrite the complex fraction as a division expression using - c. What is the quotient of? d. Suppose a bug travelsmile in 12 minutes. Write a complex fraction you could use to find the speed of the bug in miles per minute. What is the bug's speed in miles per minute?​
Mathematics
1 answer:
kenny6666 [7]3 years ago
3 0

Answer:

sooooooooooooooo long questions

Step-by-step explanation:

oh my god

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A yoga studio offers memberships that cost $20 per month for unlimited classes. The studio
Alecsey [184]

Answer:

4

Step-by-step explanation:

Each walk-in is $5, so 20 divided by 5 is 4. 4 classes.

3 0
3 years ago
What is the best estimate for the length of an ant's leg? *
Novosadov [1.4K]

Answer: about 1 cm

Step-by-step explanation:

5 0
3 years ago
I need help again don't get it
Dmitry [639]

Answer:

x=45

Step-by-step explanation:

70+65=135

180-135=45

3 0
3 years ago
Read 2 more answers
A sleep time of 15.9 hours per day for a newborn baby is at the 10h percentile of the distribution of sleep times for all newbor
Nuetrik [128]

Answer:

option (D) 16.5

Step-by-step explanation:

Data provided:

Sleep time of , X = 15.9 is at the 10th percentile

Standard deviation, σ = 0.5  hour

also,

10th percentile of normal distribution is

Z = F⁻¹(0.10)

or

Z = - 1.28  (Using Standard Normal distribution)

Now,

\\Z=\frac{X-\mu}{\sigma}

or

X = μ + ( σ × Z )

or

μ = X - ( σ × Z )

on substituting the respective values, we get

μ = 15.9 - 0.5 × (-1.28)

or

μ = 16.5

Hence, the correct answer is option (D) 16.5

8 0
3 years ago
I need help with #61 to #64 ASAP please and thank you …. Could someone please help me with it… I need to get it done ASAP
aivan3 [116]

Problem 61

The nth triangular number is

T(n) = n(n+1)/2

I'll rewrite this into

T(n) = 0.5n(n+1)

The triangular number right after this is

T(n+1) = 0.5(n+1)(n+2)

I replaced every n with n+1 and simplified

Let's see what we get when we add up the two expressions

T(n) + T(n+1)

0.5n(n+1) + 0.5(n+1)(n+2)

0.5n^2+0.5n + 0.5(n^2+3n+2)

0.5n^2 + 0.5n + 0.5n^2 + 1.5n + 1

n^2+2n+1

(n+1)^2

This shows that the sum of any two consecutive triangular numbers results in a square number

Here's a few examples

  • 0+1 = 1
  • 1+3 = 4
  • 3+6 = 9
  • 6+10 = 16
  • 10+15 = 25

Note each sum is a perfect square, which visually would plot out a square figure.

For quick reference, the set of the first few triangular numbers is {0, 1, 3, 6, 10, 15, 21, 28, 36, 45, 55,...}

<h3>Answer: Square number</h3>

==========================================================

Problem 64

Let's say we go with n = 5.

This means,

T(n) = 0.5n(n+1)

T(n-1) = 0.5(n-1)(n-1+1)

T(n-1) = 0.5n(n-1)

T(5-1) = 0.5*5(5-1)

T(4) = 10

This says that when n = 5, the 4th triangular number is 10

Triple that result and add on n = 5

3*T(4) + n = 3*10+5 = 35

This result is beyond obvious which category of figurate number it belongs to. It's not a triangular number since it's not in the form n(n+1)/2. It's not a square number either.

Through a bit of trial and error, you should find it's a pentagonal number

Pentagonal numbers are of the form n(3n-1)/2

If you plugged n = 5 into that, it leads to 35

n(3n-1)/2 = 5*(3*5-1)/2 = 5*14/2 = 70/2 = 35

The diagram shown below represents the first few pentagonal numbers. The number of blue dots corresponds to the pentagonal number itself. Note the equal spacing when dealing with dots on each segment (eg: some interior blue dots are midpoints, others are quarter points, etc.)

<h3>Answer: Pentagonal number</h3>

8 0
3 years ago
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