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Oliga [24]
3 years ago
15

Given two angles that measure 50 degrees and 90 degrees and a side that measures 4 feet​

Mathematics
2 answers:
Gemiola [76]3 years ago
8 0

Answer:The angles are the only constraint here that counts.  If one of the three interior angles of a supposed triangle is 50 degrees and another is 80 degrees, then the third angle must be 50 degrees.  Thus, we have a 50-50-80 triangle, which is isosceles though not a right triangle.  If 4 feet is a measure of one of the equal sides of a supposed triangle, then obviously the adjacent side also has measure 4 ft.

The set of angles remains the same (50-50-80), but subject to the constraint mentioned above, the measure of any one of the sides has infinitely many possible values, so long as those values are positive.

Step-by-step explanation:

kupik [55]3 years ago
7 0

What is the question? Please specific!

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You have been reading your book for about 7 days
7(10) pages each day + 9 left

70+ 9 = 69
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Given the points (5, 2) and (7, 10) find the slope of the line going through the two points . Now write the point-slope form of
drek231 [11]

Step-by-step explanation:

the slope of a line is specified as the ratio y/x. that indicates how many units y changes, when x changes a certain amount of units.

so, going e.g. from (5, 2) to (7, 10), x changes from 5 to 7 = +2 units. and y changes from 2 to 10 = +8 units.

so, the slope y/x = m = 8/2 = 4

the point-slope form is

y - y1 = m(x - x1)

m = slope

(x1, y1) = coordinates of one point on the line. let's pick the first point (5, 2).

y - 2 = 4(x - 5)

or then fully simplified (leading to the slope- intercept form) :

y - 2 = 4x - 20

y = 4x - 18

for question 2 we do the same thing for (4, -2) and (0, -5).

x changes from 4 to 0, so, -4 units.

y changes from -2 to -5, so, -3 units.

slope = y/x = m = -3/-4 = 3/4

since there is a 0 included, let's use (0, -5) as point for the point-slope form

y - -5 = 3/4(x - 0)

or

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2 years ago
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Nata [24]

Answer:

14 cm

Step-by-step explanation:

One side of the composite has a length of 6 and the other side has a length of 8.

If we add these two numbers, we'll get the missing side length of the rectangle

6 + 8 = 14 cm

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2 years ago
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

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Answer: Work

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