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AlladinOne [14]
3 years ago
6

Please hurry..........

Mathematics
1 answer:
Montano1993 [528]3 years ago
5 0

Answer:

I think the answer is C

Step-by-step explanation:

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Use the distributive property to simplify this expression: 0.1(2x+3)
soldi70 [24.7K]

\huge\text{Answer:}

\huge\mathrm{0.2x+0.3}\checkmark

\huge\text{Solution:}

Hi there, hope you are having a great day! :)

<em />\bigstar\star\star\sf{What\:is\:the\:Distributive\:Property?}

The Distributive Property is a property which states that

\longmapsto\sf{a(b+c)=ab+ac

Now, let's apply this property:

\longmapsto\sf{0.1(2x+3)

\longmapsto\sf{0.2x+0.3} (Answer)

Hope you find it helpful.

Feel free to ask if you have any doubts.

\bf{-MistySparkles^**^*

8 0
2 years ago
A hyperbola centered at the origin has verticies at (add or subtract square root of 61,0 and foci at (add or subtract square roo
deff fn [24]

Answer:

\frac{x^2}{61}-\frac{y^2}{37}  =1

Step-by-step explanation:

The standard equation of a hyperbola is given by:

\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1

where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²

Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)

The vertices is (h ± a, k) = (±√61, 0). Therefore a = √61

The foci is (h ± c, k) = (±√98, 0). Therefore c = √98

Hence:

c² = a² + b²

(√98)² = (√61)² + b²

98 = 61 + b²

b² = 37

b = √37

Hence the equation of the hyperbola is:

\frac{x^2}{61}-\frac{y^2}{37}  =1

6 0
3 years ago
The loudness of a jackhammer is a 96 dB. It sounds intense is about _____ . The Loudness of a compactor is 94 dB. It's sound int
aleksandr82 [10.1K]

Answer:

loudness of a jack hammer .004 loudness of a compactor .0025

Step-by-step explanation:

Because edge

8 0
3 years ago
Jackrabbits are capable of reaching speeds up to 40 mph. How fast is this in feet per second? (Round to the nearest whole number
Lerok [7]
Keeping in mind that there are 5280 ft in 1 mile, and there are 60 minutes in 1 hr and 60 seconds in 1 minute, therefore 60*60 seconds in 1 hr, or 3600 seconds, then.

\bf \cfrac{40\underline{mi}}{\underline{hr}}\cdot \cfrac{5280ft}{\underline{mi}}\cdot \cfrac{\underline{hr}}{3600s}\implies \cfrac{40\cdot 5280}{3600}\cfrac{ft}{s}\implies \cfrac{176}{3}\implies 58.\overline{66}\frac{ft}{s}
7 0
3 years ago
ABCD∼EFGH
DerKrebs [107]
45/75 = 30/x

30*75 = 2250/45 = 50

EF = 50 in.
6 0
3 years ago
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