Answer:
Top left: x^2 +8x +15
Top right: x^2 +3x -18
Bottom left: x^2 -3x -18
Bottom right: x^2 -10x +16
Step-by-step explanation:
= x^2 - y^2/6 * 12/(x-y)
= 6x^2 -y^2 * 72/(x-y)
= 6x^2(x-y) -y^2(x-y) * 72
= 6x^3 - 18x^2 -xy^2 + y^3 * 72
= 432x^3 - 1296x^2 -72xy^2 + 72y^3
Answer:
The half life of the car is 3.98 years.
Step-by-step explanation:
The value of the car after t years is given by the following equation:

In which V(0) is the initial value and r is the constant decay rate, as a decimal.
The value of a certain car decreases by 16% each year.
This means that 
So



What is the 1⁄2-life of the car?
This is t for which V(t) = 0.5V(0). So







The half life of the car is 3.98 years.
Step-by-step explanation:
1. 1/4(x + 12)=2 - first isolate X'
- 12 -12
2. 1/4(x) = -10 - 1/4 since its a fraction, you'll have to subtract not divide
-1/4 - 1/4
3. x = -10.25
Andre did the first step correctly, but on the second step he just divided 1.4 by -10, instead of subtract 1/4 from both sides.