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2 years ago

2 and 3/4 as a improper fraction

Mathematics

2 answers:

koban [17]2 years ago

6 0

Answer:

11/4

I hope this helps ;)

- ♥

quester [9]2 years ago

4 0

Answer:

11/4

Step-by-step explanation:

multiply 2 with 4 then add 3 which gives you 11 and you keep the denominater the same so put your 11 on top of the 4 and you get 11/4.

so always multiply the whole number with the denominater and add the numerator. whatever the sum is becomes your new numerator :))

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50 POINTS! WILL MARK BRAINLEST! NEED IN 10 - 15 MINUTES!

masha68 [24]

Answer:

(2,14)

14/2=7

14+7=21

21 is final answer

Erika had a 95% chance of guessing wrong

20 can be seen as 100%

the % will go down by 5's because of the original number

.5*20=

This will give you a 95% success rate.

7 0

2 years ago

A fair coin and a biased coin where the probability of obtaining a head is twice the probability of obtaining a tail. if both ar

Art [367]

Answer:

See below in bold.

Step-by-step explanation:

For the fair coin Prob(head) = 1/2 and Prob(Tail) = 1/2.

For the biased coin it is Prob(head) = 2/3 and Prob(Tail) = 1/3.

a) Prob(2 heads) = 1/2 * 2/3 = 1/3.

b) Prob(2 tails) = 1/2 * 1/3 = 1/6.

c) Prob(1 head ) = Prob(H T or T H) = 1/2 * 1/3 + 1/2 * 2/3) = 1/6+1/3 = 1/2.

d) Prob (at least one head) = prob (HH or TH or HT) = 1/3 + 1/2 =<em> </em>5/6.

4 0

3 years ago

If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

6 0

3 years ago

Boyle’s law states that the volume of a gas varies inversely with applied pressure. Suppose the pressure on 60 cubic meters of g

tatyana61 [14]

$\bf \qquad \qquad \textit{inverse proportional variation}
\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\textit{the volume of a gas varies inversely with applied pressure}}{v=\cfrac{k}{p}}
\\\\\\
\textit{we also know that }
\begin{cases}
v=60\\
p=1
\end{cases}\implies 60=\cfrac{k}{1}\implies 60=k
\\\\\\
\boxed{v=\cfrac{60}{p}}
\\\\\\
\stackrel{\textit{now if we apply 3 atmospheres, p=3, what is \underline{v}?}}{v=\cfrac{60}{3}}$

8 0

3 years ago

Read 2 more answers

HELP ASAP ILL GIVE A THANKS AND BRAINLIEST

larisa [96]

Answer:

-3 < x ≤ -1

Step-by-step explanation:

we know that

The solution of the graph is equal to the interval

All real numbers greater than -3 and less than or equal to -1

so the combined inequality is equal to -3 < x ≤ -1!!!!

7 0

2 years ago