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Anastaziya [24]
2 years ago
15

Help please What is the value of y in this system of equations? -6x+2y=-18 -3x-2y=54

Mathematics
1 answer:
storchak [24]2 years ago
8 0

Answer:

-6x+2y=-18 = y = -9 + 3x

-3x-2y=54 = y = -27 - \frac{3x}{2}

Step-by-step explanation:

I hope I understood this correctly.

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For accounting purposes, the value of assets (land, buildings, equipment) in a business are depreciated at a set rate per year.
lidiya [134]

Answer: $ 125987.80

Step-by-step explanation:

Given: The value, V(t) of $393,000 worth of assets after t years, that depreciate at 15% per year, is given by the formula

V (t)=V_o(b)^t, here V_o is the initial asset value  and b is the multiplicative decay factor.

The exponential decay function is given by ;-

f(x)=A(b)^x, where A is the initial value , x is the  times period and b is the multiplicative decay factor.

where b = 1-r, r is the rate of decay.

Since r = 15%=0.15

Therefore, b = 1-0.15=0.85

Now ,for 7 years , the value of assets is given by :-

V=393000(0.85)^7=125986.795\approx125987.80

Hence, the assets valued at after 7 years = $ 125987.80

4 0
2 years ago
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12*10-50 i am in a hurry
andreev551 [17]

Answer: 70

Step-by-step explanation:

12*10 = 120-50 = 70

8 0
2 years ago
Two mathematical questions attached below.
BartSMP [9]

Answer:

See below

Step-by-step explanation:

9.( {m}^{3}  {n}^{5} )^{ \frac{1}{4} }   \\   =  m^{\frac{3}{4}}n^{\frac{5}{4}}\\  \\ 10. \sqrt[5]{ \sqrt[4]{x} }  \\  =  \sqrt[5]{ {x}^{ \frac{1}{4} } }  \\  =  {( {x}^{ \frac{1}{4} } )}^{ \frac{1}{5} }  \\   =  {x}^{ \frac{1}{4}  \times  \frac{1}{5} }  \\  =  {x}^{ \frac{1}{20} }  \\  \\ \sqrt[5]{ \sqrt[3]{ {a}^{2} } }  \\  =  \sqrt[5]{ {a}^{ \frac{2}{3} } }  \\  =  {( {a}^{ \frac{2}{3} } )}^{ \frac{1}{5} }  \\   =  {a}^{ \frac{2}{3}  \times  \frac{1}{5} }  \\  =  {a}^{ \frac{2}{15} }

4 0
2 years ago
The U.S. and many other countries have recently tightened airport security. A sociologist is interested in estimating the propor
melisa1 [442]

Answer:

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

Step-by-step explanation:

Conduct a test to determine whether the true proportion of interest is higher than 0.7.

This means that the null hypothesis is: H_{0}: p = 0.7

And the alternate hypothesis is: H_{a}: p > 0.7

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

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The sociologist found that 375 of the 500 travelers randomly selected and interviewed indicated that the airports were safe.

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Probability of z being larger than 2.44, that is, a proportion larger than 0.75.

This is, looking at the z-table, 1 subtracted by the pvalue of Z = 2.44. S

Z = 2.44 has a pvalue of 0.9927

1 - 0.9927 = 0.0073

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

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3 years ago
Help please! ASAP if you can =) Picture attatched
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