The number of cars that sold on the third week is (P3=26)
The number of cars that sold on the first week is (P4=33)
<u>Step-by-step explanation:</u>
<u>Given:</u>
- The number of cars that sold on the first week is (P0=7)
- The number of cars that sold on the second week is (P0=12)
We have to find the number of cars being sold on the upcoming week
From the data given above, frame the equation
Pn = Pn −1+7 ( 12-5=7 it denotes the cars sold in the first and the second week)
Pn=5+7n (cars in the first week and the cars sold in the second week into "n" n is used to find the cars sold in the upcoming weeks)
(If n=3)
Pn=5+7(3)
Pn=26
The number of cars that sold on the third week is (P3=26)
(If n=4)
Pn=5+7(4)
Pn=33
The number of cars that sold on the first week is (P4=33)
Answer:
2 times faster
Step-by-step explanation:
because the plane takes one hour less than the bus and 60 min equal a hour and 30 plus 30 equal 60 which is a hour so then it would be 2 times as faster because it is 30 twice to equal the 60
Answer:
4
Step-by-step explanation:
The distance between the two points is (-1,-4) - (-5,-4)
Answer:
The ratio of the number of chocolates that contain nuts to the number of chocolates = 1:4
Step-by-step explanation:
The parameters given are;
Proportion of the box of chocolates that contain nuts = 1/5
Proportion of the box of chocolates that do not contain nuts = 1 - 1/5 = 4/5
Therefore, we have in a box of chocolates with five chocolates;
The number of chocolates that contain nuts = 1
The number of chocolates that do not contain nuts = 4
Which gives the ratio of the number of chocolates that contain nuts to the number of chocolates as 1:4.
Answer:
x = (y+w)/k
Step-by-step explanation:
xk-w=y
Add w to each side
xk-w+w=y+w
xk = y+w
Divide each side by k
xk/k = (y+w)/k
x = (y+w)/k