Answer:
<u>f(x) = 2(x - 2)^2 - 1</u>
<u>vertex: (2, -1)</u>
Step-by-step explanation:
f(x) = 2x^2 - 8x + 7
<em>First, we find the vertex. </em>
x = -(-8)/4 = 2
y = 2(2)^2 - 8(2) + 7 = 2(4) - 16 + 7 = 8 - 9 = -1
vertex: (2, -1)
<em>Second, we write f(x) in vertex form. </em>
<em>we know that h and k have to be 2 and -1. </em>
2x^2 - 8x + 7 = a(x - 2)^2 - 1
<em>Since 8 - 1 = 7, we do this: </em>
f(x) = (2x^2 - 8x + 8) - 1
<em>Factor out the 2 and then factor the polynomial</em>
f(x) = 2(x^2 - 4x + 4) - 1
<em>factors of 4: </em>
1 4
2 2
-1 -4
<u>-2 -2 = -4</u>
<em>the function in vertex for is: </em>
f(x) = 2(x - 2)^2 - 1
Vertex form should be : y = (x+1)^2 - 2, where the vertex is (-1,-2)
Answer:
4 1/3
Step-by-step explanation:
12/3=4
1/3+4=4 1/3
The measure of ∠ACB will be 110°
<u><em>Explanation</em></u>
According to the diagram below, 
and 
are the perpendicular bisectors of 
and 
respectively and they intersect side 
at points 
and 
respectively.
So, 
and 
Now, <u>according to the 
postulate</u>, ΔAPE and ΔCPE are congruent each other. Also, ΔCFQ and ΔBFQ are congruent to each other.
That means, ∠PCE = ∠PAE and ∠FCQ = ∠FBQ
As ∠CPQ = 78° , so ∠PCE + ∠PAE = 78° or, ∠PCE = 
° and as ∠CQP = 62° , so ∠FCQ + ∠FBQ = 62° or, ∠FCQ = 
°
Now, in triangle CPQ, ∠PCQ = 180°-(78° + 62°) = 180° - 140° = 40°
Thus, ∠ACB = ∠PCE + ∠PCQ + ∠FCQ = 39° + 40° + 31° = 110°
Answer:
6 = 8 + 9n
Step-by-step explanation:
Based on the problem, you can also do this:
8 + 9n = 6
I am joyous to assist you anytime.
