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Iteru [2.4K]
3 years ago
9

I’m getting ahead easily but I’m stuck with this question.

Mathematics
1 answer:
Kruka [31]3 years ago
8 0

Answer:

I know #1 but not #2 it's

(10x2)+4=24 it's still less then 25 :)

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What is the surface area of the composite solid? a rectangular prism with a length of 2 meters, width of 8 meters, and height of
Anna007 [38]

Using the formula for the surface area of a rectangular prism, the surface area of the composite solid is: C. 162m²

<h3>What is the Surface Area of a Rectangular Prism?</h3>

Surface area of a rectangular prism = 2(wl+hl+hw)

Surface area of the composite shape = surface area of the larger prism + surface area of the smaller prism - area of the face both prisms are joined together

Surface area of the larger prism = 2(wl+hl+hw) = 2(2×3 + 9×3 + 9×2) = 102 m²

Surface area of the smaller prism = 2(wl+hl+hw) = 2(2×8 + 2×8 + 2×2) = 72 m²

Area of the face both prisms are joined together = 2(l×w) = 2(3 × 2) = 6 m²

Surface area of the composite shape = (102 + 72) - 12 = 162m²

Learn more about surface area of rectangular prism on:

brainly.com/question/1310421

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4 0
2 years ago
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=. Diego and Priya are each saving money. Diego starts with $80 in his savings account and adds $5
stellarik [79]

Answer:

diego. 80+(5x3)= 95

it isn't priya because 30+(5x3)=45

3 0
3 years ago
Make p the subject of the formula q-2p=p+4
Nutka1998 [239]

Answer:

q-2p=p+4

q-4=p+3p

p=(q-4)/3is answer

4 0
3 years ago
Help with fraction proprtions
Marina86 [1]
The first one is 100%
7 0
3 years ago
Let​ T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear​ transformation, and
Klio2033 [76]

Answer:

\{T(v_1), T(v_2), T(v_3)\} is linearly dependent set.

Step-by-step explanation:

Given:  \{v_1,v_2,v_3\} is a linearly dependent set in set of real numbers R

To show: the set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

Solution:

If \{v_1,v_2,v_3,...,v_n\} is a set of linearly dependent vectors then there exists atleast one k_i:i=1,2,3,...,n such that k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0

Consider k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

A linear transformation T: U→V satisfies the following properties:

1. T(u_1+u_2)=T(u_1)+T(u_2)

2. T(au)=aT(u)

Here, u,u_1,u_2∈ U

As T is a linear transformation,

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\

As \{v_1,v_2,v_3\} is a linearly dependent set,

k_1v_1+k_2v_2+k_3v_3=0 for some k_i\neq 0:i=1,2,3

So, for some k_i\neq 0:i=1,2,3

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

Therefore, set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

6 0
3 years ago
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