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777dan777 [17]
3 years ago
7

What is the first step in the construction of a line perpendicular to `stackrel(harr)(AB)` and passing through an external point

M? Assume that the construction uses only a compass and a straightedge.
Mathematics
1 answer:
melisa1 [442]3 years ago
6 0

take your compass on a point on your line. then draw a circle. take the 2 points in which the circle hit the line and draw 2 circles larger than half the distance between he 2 points. take the point that they intersect and and connect it to the line and you point M and it is purpendicular. does that make sense?

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Select the correct answer from each drop-down menu.
Anit [1.1K]

Answer:

  • 3^x
  • 9, 15, 33, 87, 249
  • (4, 87) for example

Step-by-step explanation:

a) First differences of the f(x) values in the table are ...

  19 -13 = 6, 37 -19 = 18, 91 -37 = 54, 253 -91 = 162

The second differences are not constant:

  18 -6 = 12, 54 -18 = 36, 162 -54 = 108

But, we notice that both the first and second differences have a common ratio. This is characteristic of an exponential function. The common ratio is 18/6 = 3, so the parent function is 3^x.

__

b) Translating a function down 4 units subtracts 4 from each y-value. The values of f(x) in the table would be ...

  9, 15, 33, 87, 249

__

c) The x-values of the function stay the same for a vertical translation, so the points in the table of the transformed function are ...

  (x, f(x)) = (1, 9), (2, 15), (3, 33), (4, 87), (5, 249)

8 0
3 years ago
Meg is a veterinarian. In a given week, 50% of
neonofarm [45]
Meg would be a to be correct
7 0
3 years ago
There are 42 children in the classroom each student will get 28 pencils and 46 erasers how many pencils will the teacher have to
Aleksandr-060686 [28]

Since the question is asking how many pencils the teacher will have to give out, we can automatically ignore the 46 erasers from the problem because it is not relevant. The information was most likely put there to confuse you.

Each student is getting 28 pencils, so if we multiply the number of students by 28 pencils, we will find how many pencils the teacher will need to give out.

There are 42 children in the classroom, so multiply 42 by 28.

42 * 28 = 1,176

The teacher will have to give out <u>1,176 pencils</u> to her 42 children in the classroom.

4 0
3 years ago
Read 2 more answers
John has $220 in his account and adds $25 to it each month Cheryl has $100 in her account and adds $35 each to her account. How
sammy [17]

Answer: In 12 months they will have the same amount, which will be $520.

Step-by-step explanation:

220 + 25m = 100 + 35m

m = month

Subtract 100 from each side

120 + 25m = 35m

Subtract 25m from each side

120 = 10m

Divide each side by 10

12 = m

4 0
3 years ago
Read 2 more answers
1: Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not hav
OLga [1]

Answer:

(1) y=C, C\neq0

(2) x=C

(1) y=0

Step-by-step explanation:

For the linear equation, the power on the solitary variable must be 1.

When the graph of a function crosses/ touches the x-axis than the equation has solution/solutions otherwise it does not has a solution.

When it touches/cresses the x-axis for infinite times then it will have an infinite number of solutions.

(1) The linear equation y-C=0, where y is a variable and C is a non-zero constant,  C \neq 0, has the graph parallel to the x-axis. It has no solution as the graph will never cross/touch the x-axis.

Algebraically, in linear equation y-C=0, is independent of x, so there is no value of x for the solution to be exist.

(2) The linear equation x-C=0, where x is a variable and C is a constant, has one solution.

The solution for the equation is

x-C=0

\Rightarrow x=C, where C\neq0.

(3) The linear equation y=0, where y is a variable, has the graph coinciding with the x-axis. So, it has infinitely many solutions.

Algebraically, in linear equation y=0, is independent of x, so for all value of x, the given equation is zero. Hence, there are infinitely many solutions.

3 0
3 years ago
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