Given a straight line PQ has a gradient of 3 and passes through a point (4,7)
1 answer:
Answer:
Assign variables to the coordinates of the given points
Let the coordinates of P be (x1;y1) and Q(x2;y2)
x1=−1;y1=−5;x2=5;y2=4
Write down the two-point form of the straight line equation
y−y1x−x1=y2−y1x2−x1
Substitute the values and make y the subject of the equation
y−(−5)x−(−1)y+5x+1y+5y+5y=4−(−5)5−(−1)=96=32(x+1)=32x+32=32x−72
Write the final answer
y=32x−312
Step-by-step explanation:
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i need more info
que?
Answer: -7 < k < 7
Step-by-step explanation: