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rewona [7]
3 years ago
9

A'B'C' is a dilation image of ABC. Which is the correct description of the dilation?

Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

Answer:

The second option is the answer.

Step-by-step explanation:

The center of a dilation makes all the corresponding vertices coincide at one point if we draw a straight line including that pre image and new image point. All coordinates correspond about Point C. So the first two options are the viable answers.

The blue triangles right side measure is 10 while the smaller triangle right side measure is 5. This means the scale factor is

p = kx

10 = 5x

x = 2

So our scale factor is 2.

The second option is the answer.

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Simplify the expression 1/√(1-cos^2 x) . Remember cos x= 1/csc x
Cerrena [4.2K]
First, we are going to use the Pythagorean identity: sin^2(x)+cos^2(x)=1 to rewrite our expression. Solving for sin^2(x) in our Pythagorean identity  we get that sin^2(x)=1-cos^2(x), so we can rewrite our expression as follows:
\frac{1}{ \sqrt{1-cos^2(x)} } = \frac{1}{ \sqrt{sin^2(x)} } = \frac{1}{sin(x)}

Next, we are going to use the trig identity: csc(x)= \frac{1}{sin(x)} to completely simplify our expression:
\frac{1}{sin(x)} =csc(x)

We can conclude that \frac{1}{ \sqrt{1-cos^2(x)} }=csc(x)
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Can someone help me with this math hw ​
AveGali [126]

Answer:

Step-by-step explanation:

F(x) = x² - 2x + 1

      = (x - 1)²

By comparing this equation with the vertex form of the quadratic equation,

y = (x - h)² + k

Here, (h, k) is the vertex

Vertex of the parabola → (1, 0)

x-intercepts → (x - 1)² = 0

                       x = 1

y-intercepts → y = (0 - 1)²

                       y = 1

Now we can draw the graph of the given function,

From this graph,

As x → 0,

\lim_{x \to 0^{-}} (x-1)^2=1

\lim_{x \to 0^{+}} (x-1)^2=1

f(0) = (0 - 1)²

     = 1

Since, \lim_{x \to 0^{-}} (x-1)^2=\lim_{x \to 0^{+}} (x-1)^2=1

Therefore, given function is continuous at x = 0.

8 0
3 years ago
Find the slope of the line passing through the points <br> , −8−3<br> and <br> , −34<br> .
alukav5142 [94]

Slope of the line passing through two points <span><span>P=<span>(<span><span>x1</span>,<span>y1</span></span>) </span></span></span>and <span><span>Q=<span>(<span><span>x2</span>,<span>y2</span></span>)</span></span></span> is given by <span><span>m=<span><span><span>y2</span>−<span>y1/</span></span><span><span>x2</span>−<span>x1</span></span></span></span></span>.

We have that <span><span><span>x1</span>=−8</span></span>, <span><span><span>y1</span>=−3</span></span>, <span><span><span>x2</span>=−3</span></span>, <span><span><span>y2</span>=4</span></span>.

Plug given values into formula for slope: <span><span>m=<span><span><span>(4)</span>−<span>(<span>−3</span>)/</span></span><span><span>(<span>−3</span>)</span>−<span>(<span>−8</span>)</span></span></span>=<span>7/5</span></span></span>.

Now y-intercept is <span><span>b=<span>y1</span>−m⋅<span>x1</span></span></span> .

<span><span>b=−3−<span>(<span>7/5</span>)</span>⋅<span>(<span>−8</span>)</span>=<span>41/5.</span></span></span>

Finally, equation of the line can be written in the form <span><span>y=mx+b</span></span>.

<span><span>y=<span>7/5</span>x+<span>41/5</span></span></span>

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MA_775_DIABLO [31]

Answer:

3.167

Step-by-step explanation:

Hope this helps

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3 years ago
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