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grandymaker [24]
3 years ago
5

I need help solving this. Thank you too those who respond

Mathematics
1 answer:
azamat3 years ago
4 0

Answer:

Its D on edge because yes im 100% right

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Marcus asked 10 people at a juggling festival what age they were when they started to juggle
Scrat [10]

Question

Marcus asked 10 people at a juggling festival what age they were when they started to juggle. Which interval contains the median age?

Answer:

See Explanation

Step-by-step explanation:

Given

n = 10

Required

The median interval

The question is incomplete, as the required data is not given.

To solve this question, I will use the following assumed dataset.

Age:17\ 17\ 18\ 20\ 21\ 22\ 22\ 24\ 28\ 28

First, calculate the median position.

Median = \frac{n+1}{2}\ th

Median = \frac{10+1}{2}\ th

Median = 5.5\ th

This implies that the median is the mean of the 5th and 6th data

So, we have the interval to be.

Median = [5th, 6th]

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<em>Generally, the median of 10 data set is located at interval 5 to 6</em>

6 0
3 years ago
(x+3)(x−2)/(x+7)^2 ≥0
LiRa [457]

Answer:

(x+3)(x−2)/(x+7)^2 ≥0 when  x ≤ -3 or x  ≥ 2.

Step-by-step explanation:

(x+3)(x−2)/(x+7)^2 ≥0

The critical values are (x + 3)(x - 2) = 0.

That is when x = -3 and x = 2.

Set up a table:

            x < - 3     x = -3    -3 < x < 2   x = 2   x > 2

x + 3        -ve           0               +ve       0         +ve

x - 2         -Ve         -ve              -ve       0          +ve

(x+7)^2       +ve       +ve             +ve        +ve       +ve

Whole

function    + ve        0                - ve        0          +ve

So the function is ≥ 0  when x ≤ -3 and x  ≥ 2.

6 0
3 years ago
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