Firstly, found out a square that is 7cm long and 5cm wide, you get the 7 from adding 5+2 across the top. Don't forget that, 2cm = 5m so you get the real area we need to work out how many meters are in each length.
So, firstly you know that in 1 cm there is 2.5m, with this information you can then do 7x2.5 to get the distance across the top in meters. That gives you 17.5 megers for the top and 5x2.5 = 12.5m.
After finding that, you have to find the area of this square, so you do 17.5m x 12.5m = 218.75m^2 for the biggest square, that's the total area however we want the bedroom area.
Therefore we have to workout how much area is in the living room and take that away from the total amount. Since we found out how many meters are in the 5cm we can use that here again. 12.5m x 12.5m = 156.25m^2 with this we do 218.75m^2 - 156.25m^2 = 62.5m^2 is for the bedroom and small empty space. now we just need to find the small empty space.
To do that, we do 5-4 which leave us with 1 cm and we already know it's across length is 2, with the information provided and stated we know that it's 2.5m x 5m = 12.5m^2
Then finally we do 62.5m^2 - 12.5m^2 to get the bedroom area. <u>50m^2</u>
Answer: B. 30
Step-by-step explanation:
First, you re-write the expression
6(-3.5) + 15(4) - 12(3/4)
Then multiply all the parts correctly.
-21 + 60 - 9
-21 + 60 = 39
-9
= 30
Let:
x = Pounds of walnuts in the mix.
Each pound of walnuts costs $0.80. thus x pounds of walnuts cost 0.8x dollars.
Each pound of cashews costs $1.25 and the mix will contain 8 pounds of cashews, so the cost is 8*$1.25 = $10
The total cost of the mix is, therefore: 0.8x + 10 dollars.
We are also given the pound of mix costs $1.00 and we have a total of 8 + x pounds, so the total cost of the mix is 1*(8 + x) dollars.
Equating both costs:
0.8x + 10 = 1*(8 + x)
Operating:
0.8x + 10 = 8 + x
Subtracting x and 10:
0.8x - x = 8 - 10
Simplifying:
-0.2x = -2
Dividing by -0.2:
x = -2/(-0.2)
x = 10
Answer: 10 pounds
Answer: f(2) = 4
Step-by-step explanation:
F(x) and g(x) are said to be continuous functions
Lim x=2 [3f(x) + f(x)g(x)] = 36
g(x) = 2
Limit x=2
[3f(2) + f(2)g(2)] = 36
[3f(2) + f(2) . 6] = 36
[3f(2) + 6f(2)] = 36
9f(2) = 36
Divide both sides by 9
f(2) = 36/9
f(2) = 4
