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2 years ago

What TWO expressions equal 12−(−33) ?

Mathematics

1 answer:

erastova [34]2 years ago

8 0

Answer:

12+33 and 33 - (-12)

Step-by-step explanation:

12 - (-33) = 45

12 + 33 gives us 45

33 - (-12) gives us 45

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Helppp pleaseeee!!!!

Savatey [412]

Answer:

Initial value = 4

Growth factor = 1.6

Step-by-step explanation:

Function representing the exponential growth is given by,

f(x) = Initial value(1 + growth rate)ˣ

Here x = time or duration for growth

(1 + growth rate) = Growth factor

Given function is,

f(x) = 4(1.6)ˣ

By comparing both the functions,

Initial value = 4

Growth factor = 1.6

4 0

3 years ago

Last year, Jina opened an investment account with $8200. At the end of the year, the amount in the account had decreased by 6.5%

adoni [48]

Answer:

$250.69 maybe?

Step-by-step explanation:

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3 years ago

30 points Someone help im very confused.

Alchen [17]

Answer:

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Step-by-step explanation:

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2 years ago

A company produces and sells widgets and gizmos. In January the company sold 350 items for a total of $9,000. If each widget sol

iren [92.7K]

Answer:

The company sold 100 widgets and 250 gizmos.

Step-by-step explanation:

Let $x_1$ be the number of widgets sold and $x_2$ be the number of gizmos sold.

We are told that the company sold 350 items. We can represent this information in an equation as:

$x_1+x_2=350...(1)$

We have been given that a each widget sold for $35 and each gizmo sold for $22. The company sold 350 items for a total of $9,000.

We can represent this information in an equation as:

$35x_1+22x_2=9,000...(2)$

From equation (1), we will get:

$x_2=350-x_1$

Substitute this value in equation (2):

$35x_1+22(350-x_1)=9,000$

$35x_1+7,700-22x_1=9,000$

$13x_1+7,700=9,000$

$13x_1+7,700-7,700=9,000-7,700$

$13x_1=1,300$

$\frac{13x_1}{13}=\frac{1,300}{13}$

$x_1=100$

Therefore, the company sold 100 widgets.

Substitute $x_1=100$ in equation (1):

$100+x_2=350$

$100-100+x_2=350-100$

$x_2=250$

Therefore, the company sold 250 gizmos.

3 0

2 years ago

Read 2 more answers

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by

$g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}$ , and

$P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx$ = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0

2 years ago