Question

What is the approximate area of the octagon? 71 ft2 101 ft2 110 ft2 202 ft2

Answer 1

Answer:

101   i hope this helps

Step-by-step explanation:

Given: A standard octagon has a span of 6 ft and a side length of 4.6 ft.  

To discover the territory of a normal octagon(A) of side length an is given by :  

$A=2*(1+\sqrt{2})a^{2}$

Given the length of side, a= 4.6 ft  

Substitute the estimation of a=4.6 ft in the given equation of zone:  

$A=2*(1+\sqrt{2} )*(4.5)^{2}$

or then again  

$A=(2+2\sqrt{2} )*(21.16)$

or then again  

$A=(2+2.828) *(21.16)$

Streamline:  

$A=4.828*21.16=102.16048 ft^{2}$

along these lines, the inexact zone of ordinary octagon is, 101 square ft

Answer 2

Answer:

101

Step-by-step explanation: