Answer:
C₂₃ = -186
↓
C₁₃ = -32
↓
C₃₁ = 6
↓
C₁₁ = 27
↓
C₂₁ = 28
↓
C₃₃ = 38
↓
C₂₂ = 56
↓
C₃₂ = 90
↓
C₁₂ = 115
Step-by-step explanation:
The given matrices are;
The cross product of the matrices is found as follows;
C₁₁ = 1×5 + 7×3 + (-1) × (-1) = 27
C₁₂ = 1×1 + 7×15 + (-1)×(-9) = 115
C₁₃ = 1×7 + 7×(-2) + (-1)×25 = -32
C₂₁ = 5×5 + (-2)×3 + (-9) × (-1) = 28
C₂₂ = 5×1 + (-2)×15 + (-9)×(-9) = 56
C₂₃ = 5×7 + (-2)×(-2) + (-9)×25 = -186
C₃₁ = (-3)×5 + 8×3 + 3 × (-1) = 6
C₃₂ = (-3)×1 + 8×15 + 3×(-9) = 90
C₃₃ = (-3)×7 + 8×(-2) + 3×25 = 38
Therefore, we get;
In increasing order, we have;
C₂₃ = -186
↓
C₁₃ = -32
↓
C₃₁ = 6
↓
C₁₁ = 27
↓
C₂₁ = 28
↓
C₃₃ = 38
↓
C₂₂ = 56
↓
C₃₂ = 90
↓
C₁₂ = 115
Answer:
a) y-intercept (as can be seen) is 50 degrees
b) this means that, at the time the temperature began to be recorded, it was 50 degrees outside
Step-by-step explanation:
We know that
the equation of the line in <span>slope-intercept form--------------> y=mx+b
Part A)
</span>Passing through (2,5) and perpendicular to the line whose equation is -3x+y-6=0
<span>Step 1
find the slope m
</span><span>remember that if two lines are perpendicular mi*m2=-1
</span>-3x+y-6=0---------> y=3x+6-------------> m1=3
then
m2=-1/3
Step 2
find the value of b
point (2,5) m=-1/3
y=mx+b----------> 5=(-1/3)*2+b--------> b=5+(2/3)-----> b=17/3
Step 3
find the equation of the line in slope-intercept form
y=(-1/3)x+17/3
using a graph tool
see the attached figure
the answer part A) is y=(-1/3)x+17/3Part B)
Passing through (2,5) and perpendicular to the line whose equation is -3x-6=7x; slope intercept form.
Step 1
-3x-6=7x---------> 10x=-6 -----> x=-6/10-----> x=-3/5 (parallel to the axis y)
equation of the line is a constant so its perpendicular will be another constant defined by the coordinate y of the point through which it passes parallel to the axis x
point (2,5) ----------> the coordinate y=5
therefore
the perpendicular line is y=5 (parallel to the axis x)
using a graph tool
see the attached figure
the answer part B) is y=5
Sure, 1134 could be a reasonable answer but for what