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Anettt [7]
3 years ago
9

F(x)=x^2+9x-16 What is vertex Axis of semetry

Mathematics
2 answers:
UNO [17]3 years ago
5 0

Answer:

axis of symmetry is x=\frac{-9}{2}.

The ordered pair of the vertex is (\frac{-9}{2},\frac{-145}{4}).

Step-by-step explanation:

Your function is a quadratic.

Compare x^2+9x-16 to ax^2+bx+c.

You should see that a=1,b=9,c=-16.

The x-coordinate of the vertex or the axis of symmetry since the axis symmetry goes through the vertex can be found by computing \frac{-b}{2a}.

So here we go!

The axis of symmetry is x=\frac{-9}{2(1)}=\frac{-9}{2}.

When you write your axis of symmetry be sure to write it as an equation.

That is the axis of symmetry is x=\frac{-9}{2}.

Now that was also the x-coordinate of your vertex.  To find the corresponding y-coordinate of the vertex, plug your value for x into

y=x^2+9x-16.

y=(\frac{-9}{2})^2+9(\frac{-9}{2})-16

Put into calculator:

y=\frac{-145}{4} when x=\frac{-9}{2}

The ordered pair of the vertex is (\frac{-9}{2},\frac{-145}{4}).

Verdich [7]3 years ago
4 0

Answer:

Vertex: (h,k)\rightarrow(-4.5,-36.25)

Axis of symmetry: x=-4.5

Step-by-step explanation:

<h3>Finding the Axis of Symmetry:</h3>

First I'll find the axis of symmetry. This formula lets us find the a.o.s: x=\frac{-b}{2a}.

In x^2+9x-16, the values of a, b, and c are:

  • a: 1
  • b: 9
  • c: -16

We only need a and b to find the axis of symmetry. Substitute these values into the formula.

  • x=\frac{-(9)}{2(1)}

Simplify this fraction.

  • x=\frac{-9}{2} =-4.5

The axis of symmetry of this quadratic function is x = -4.5.

<h3>Finding the Vertex:</h3>

Now to find the vertex, we have to take into account that this quadratic is in standard form, making it a little harder. We have to convert this function into vertex form.

Start by changing f(x) to 'y' and adding 16 to both sides.

  • y+16=x^2+9x

Use the completing the square formula: (\frac{b}{2} )^2

  • (\frac{9}{2} )^2=20.25

Keep the balance by adding 20.25 on the left side and adding it on the right side of the equation.

  • y+16+20.25=x^2+9x+20.25

Combine like terms.

  • y+36.25=x^2+9x+20.25

Factor the right side of the equation. Ask yourself, "What two numbers multiply to 20.25 (c) and add up to 9 (b)?" These two numbers are 4.5 and 4.5. Rewrite the right side with factors.

  • y+36.25=(x+4.5)(x+4.5)
  • y+36.25=(x+4.5)^2

Isolate y by subtracting 36.25 from both sides of the equation.

  • y=(x+4.5)^2-36.25

Now this quadratic function is in vertex form, making it super simple to find the vertex using (h, k).

Vertex form of a quadratic is:

  • y=a(x-h)^2+k

Compare y=(x+4.5)^2-36.25 with the original vertex form and find where h and k are. Those are the x (h) and y (k) values of the vertex.

Since the original vertex form has x - h, the h value in y=(x+4.5)^2-36.25 would be a negative since two negatives make a positive. The k value would stay "normal"---negative would mean it is a negative and positive would mean it is a positive number.

Therefore the h value is -4.5, and the k value is -36.25.

The ordered pair of the vertex is (-4.5, -36.25).

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