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emmasim [6.3K]
3 years ago
11

PLEASE I WILL GIVE BRAINLIEST IF ONLY UR CORRECT.

Mathematics
1 answer:
patriot [66]3 years ago
3 0

Answer:

Mary removed the dollar sign from (X.)

We know this because $4.00x$5.00=$20.00 so that’s correct and we know that $12.50x $4.00=$50.00. So, our only error here is that there is no dollar sign in our (X) numbers. So that is Mary’s mistake. We can correct it by simply adding a dollar sign to 20 to make $20.00 and adding another dollar sign to 50 to make $50.00

Step-by-step explanation:

hope this helps

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An airplane is flying at a height of 5 kilometers above the ground. The distance along the ground from the airplane to the airpo
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\rule{70mm}{2.9pt}

\large \sf{✟ \: Problem \: ✟} :

An airplane is flying at a height of 5 kilometers above the ground. The distance along the ground from the airplane to the airport is 7 kilometers. What is the angle of depression from the airplane to the airport? (Write the answer to the nearest degree.)

\rule{70mm}{2.9pt}

\large \sf{✟ \: Solution \: ✟} :

✞ Step 1 ✞: Identify what is asked in the problem.

❒ The angle of depression from the airplane to the airport.

✞ Step 2 ✞: Use appropriate trigonometric ratio to solve the problem.

❒ Since the two legs of the right triangle are part of the problem, hence we use tangent ratio:

\qquad \qquad \bigstar \:  \: \boxed{\tt{ \quad \tan A \degree =  \frac{5}{7}  \quad}}

✞ Step 3 ✞: Solution and interpretation.

:  \qquad \large \implies \tt{ \tan A =  \frac{5}{7} }

:  \qquad \large \implies \tt{A =   \tan^{ - 1}(\frac{5}{7} )}

:  \qquad \large \implies \tt{A =  35.54 \approx \pmb{36 \degree}}

\rule{70mm}{2.9pt}

\large \sf{✟ \: Answer \: ✟} :

Hence, the angle of depression from the airplane to the airport is approximately 36°.

\rule{70mm}{2.9pt}

\large \bold{✰ \: MrHarold \: ࿐}

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