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erica [24]
3 years ago
12

Which expression represents the distance between point (0, a) and point (a, 0) on a coordinate grid?

Mathematics
2 answers:
o-na [289]3 years ago
5 0

Answer:

\sqrt{2} a

Step-by-step explanation:

The distance between point (x1,y1) and (x2,y2) on a coordinate plane is given by expression \sqrt{(x1-x2)^2+(y1-y2)^2}

In the problem given coordinate points are

(0, a) and (a, 0).

Thus, distance between these points are given by

distance = \sqrt{(x1-x2)^2+(y1-y2)^2}\\=>distance = \sqrt{(0-a)^2+(a-0)^2}\\=>distance = \sqrt{(a)^2+(a)^2}\\\\=>distance = \sqrt{2a^2}\\=>distance = \sqrt{2} a

Thus , expression \sqrt{2} a gives the distance between point (0, a) and point (a, 0) on a coordinate grid.

olasank [31]3 years ago
3 0

Answer:

A) √2a^2

Step-by-step explanation:

I just took the quiz on edge

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A 95% confidence interval for a population mean is computed from a sample of size 400. Another 95% confidence interval will be c
Anna [14]

Answer:

The interval from the sample of size 400 will be approximately <u>One -half as wide</u> as the interval from the sample of size 100

Step-by-step explanation:

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the 95% confidence interval is dependent on the value of the margin of error at a constant sample mean or sample proportion

Generally the margin of error is mathematically represented as

      E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }    

Here assume that Z_{\frac{\alpha }{2} } \ and \  \sigma \ is constant so

     E =  \frac{k}{\sqrt{n} }

=>  E \sqrt{n} = K

=>   E_1 \sqrt{n}_1 =  E_2 \sqrt{n}_2

So  let  n_1 = 400 and n_2 =  100

=>   E_1 \sqrt{400} =  E_2 \sqrt{100}

=>  E_1 =  \frac{\sqrt{100} }{\sqrt{400} } E_2

=>  E_1 =  \frac{1}{2 } E_2

So From this we see that  the confidence interval for a sample size of 400 will be half that with a sample size of 100

   

     

   

7 0
3 years ago
a sequence has a first term of 2 and a constant ratio of _3/2 what are the first five terms of the sequence
soldi70 [24.7K]
This is a geometric sequence with a=2, r= -3/2.
Therefore,
a₁ = 2
a₂ = 2*(-3/2) = -3
a₃ = 2*(-3/2)² = 9/2 = 4.5
a₄ = 2(-3/2)³ = -27/4 = -6.75
a₅ = 2(-3/2)⁴ = 81/8 = 10.125

Answer:
In fractions, the first five terms are
     2, -3, 9/2, -27/4, 81/8
In decimals, the first five terms are
     2.000, -3.000, 4.500, -6.750, 10.125


5 0
3 years ago
5(x+3)-7(6-3)+29=50-3(8-x)
Sveta_85 [38]

Answer:

\quad x=\frac{3}{2}

Step-by-step explanation:

7\left(6-3\right)=21, \mathrm{Expand\:}5\left(x+3\right)-21+29:\quad5x+23, \mathrm{Expand\:}50-3\left(8-x\right):\quad 3x+26, Subtract 23 and 3x from both sides and simplify: 2x=3, Divide both sides by 2 and simplify: x=\frac{3}{2}

<em>Hope this helps!!!</em>

6 0
3 years ago
Plz help I have no clue how to do 1 and 2
Elan Coil [88]
1) y= 1/2x+2 and I have no idea about 2
3 0
3 years ago
Female athletes at the University of Colorado, Boulder, have a long-term graduation rate of 67% (Source: Chronicle of Higher Edu
VLD [36.1K]

Answer:

Yes, we can assume that the percent of female athletes graduating from the University of Colorado is less than 67%.

Step-by-step explanation:

We need to find p-value first:

z statistic = (p⁻ - p0) / √[p0 x (1 - p0) / n]

p⁻ = X / n = 21 / 38 = 0.5526316

the alternate hypothesis states that p-value must be under the normal curve, i.e. the percent of female athletes graduating remains at 67% 

H1: p < 0.67 

z = (0.5526316 - 0.67) / √[0.67 x (1 - 0.67) / 38] = -0.1173684 / 0.076278575

z = -1.538681 

using a p-value calculator for  z = -1.538681, confidence level of 5%

p-value = .062024, not significant

Since p-value is not significant, we must reject the alternate hypothesis and retain the null hypothesis.

3 0
3 years ago
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