Answer:
By a theorem we learned, i. and ii. are valid under the assump- tion that the sequences (a n)1 n=1and (b n) 1 n=1are convergent. For iii.]
Step-by-step explanation:
Lol... I don't know if this is a joke, but it's basically just restating the precious problem, but switching numbers. So the answer would be 2,592.
Answer:
16-2n=-8+4n-12
16+8+12=4n
36/4=n
9=n
Step-by-step explanation:
The correct answer would be b. range. you take the largest amount and subtract the smallest amount giving you the range.
