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2 years ago

No.14 Please help me

Mathematics

1 answer:

Ulleksa [173]2 years ago

8 0

Answer:

A) 11.25 m

B) 3.4s

C) 0.75

Step-by-step explanation:

A) Put in given time. Then, y = 11.25m

B) If the object is at ground, then y = 0.

So, 0 = 17t - 5t^2 => t = 0 or 3.4 [ 0s is initial height, so it's not valid ]

C) H1 = 17*(1.5+1) - 5*((1.5+1)^2) = 11.25

H2 = 17*1 - 5*(1^2) = 12

H2 - H1 = 0.75

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(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

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