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fenix001 [56]
3 years ago
10

What is the value of x?

Mathematics
1 answer:
Oxana [17]3 years ago
5 0
Hi there!

To solve this problem, we'll need to proceed methodically. First, we'll find the value of ST. Using the 30-60-90 relationship, we know that ST is equal to 2. Then, we need to find the value of RT. Again using the 30-60-90 relationship, we know that RT is equal to 4. Lastly, using the 45-45-90 relationship, we know that x = 4.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
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Kaya's family spends $105 to rent a boat for 7
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A: $45 for 3 days

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Step-by-step explanation:

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zlopas [31]

We are given with a quadratic equation which represents a Parabola , we need to find the vertex of the parabola , But let's recall that , For any quadratic equation of the form ax² + bx + c = 0 , the vertex of the parabola is given by ;

{\quad \qquad \boxed{\bf{Vertex = \left(\dfrac{-b}{2a},\dfrac{-D}{4a}\right)}}}

Where , D = b² - 4ac (Discriminant)

Now , On comparing the given equation with ax² + bx + c , we have

⇢⇢⇢ <em><u>a = 1 , b = - 10 , c = 2</u></em><em><u>7</u></em>

Now , Calculating D ;

{:\implies \quad \sf D=(-10)^{2}-4\times 1\times 27}

{:\implies \quad \sf D=100-108}

{:\implies \quad \bf \therefore \quad D=-8}

Now , Calculating the vertex ;

{:\implies \quad \sf Vertex =\bigg\{\dfrac{-(-10)}{2\times 1},\dfrac{-(-8)}{4\times 1}\bigg\}}

{:\implies \quad \sf Vertex = \left(\dfrac{10}{2},\dfrac{8}{2}\right)}

{:\implies \quad \bf \therefore \quad Vertex = (5,2)}

Hence , The vertex of the parabola is at (5,2)

Note :- As the Discriminant < 0 . So , the equation will have imaginary roots .

Refer to the attachment for the graph as well .

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$47 (discount: 30%)
ZanzabumX [31]

Answer:

Discount: $14.10

Sales Price: $32.90

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Read 2 more answers
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