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1 year ago

I need it ASAP. Solve it please!! {z}^{3} - 8i = 0

Mathematics

1 answer:

labwork [276]1 year ago

6 0

Step-by-step explanation:

one of the cube roots (there are 3 of them) is

81/3[cos(270°/3) + isin(270°/3)] = 2(cos90° + isin90°) = 2i

The 3 cube roots are equally spaced around the circle centered at (0,0) with radius 81/3 = 2

360° / 3 = 120°

Another cube root of -8i is

2[cos(90° + 120°) + isin(90° + 120°)] = 2[cos(210°) + isin(210°)] = 2(-√3/2 + i(-1/2)) = -√3 - i

The third cube root of -8i is

2[cos(90°+2(120°)) + isin(90°+2(120°)) = 2[cos330° + isin(330°)] = 2[√3/2 +i(-1/2)] = √3 - i

So, the cube roots of -8i are 2i, -√3 - i, and √3 - i

You might be interested in

Y=−2x+4y, equals, minus, 2, x, plus, 4

vlabodo [156]

The missing value of the solution to the equation y = −2x + 4, is: 3.

<h3>What is the Solution to an Equation?</h3>

The solution to a given equation, is the x and y values of an ordered pair that would make the equation true, if we substitute their values into the equation.

Given the equation, y = -2x + 4, and we have (x, -2) as the solution where the value of x is the missing value in the solution, to find the value of x, substitute y = -2 into the equation and solve for x:

-2 = -2x + 4

Subtract 4 from both sides

-2 - 4 = -2x + 4 - 4 (subtraction property of equality)

-6 = -2x

Divide both sides by -2

-6/-2 = -2x/-2

3 = x

x = 3

Therefore, the missing value is: 3.

Learn more about the solution to an equation on:

brainly.com/question/25678139

#SPJ1

3 0

2 months ago

Does anyone understand this

melomori [17]

I hope this helps you

7 0

2 years ago

The gross weight of a truck containing 30 pigs is 8 tons 1,123 pounds and 6 ounces. The average weight of one pig is 95 pounds 1

irakobra [83]

Answer: The net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

The weight of the empty truck is 7 tons 254 pounds 10 ounces.

Step-by-step explanation:

Since we have given that

The gross weight of a truck containing 30 pigs = 8 tons 1123 pounds 6 ounces

Average weight of one pig = 95 pounds 10 ounces

Now,

We know that

$1\text{ pound}=16\text{ ounces}$

So,

$\text{Gross weight of truck containing 30 pigs}\\=8\text{ tones }1123\times 16+6\text{ ounces}\\=8\text{ tons }17974\text{ ounces}$

Similarly,

$\text{ average weight of one pig }\\=95\times 16+10\text{ ounces}\\=1530\text{ ounces}$

So, Net weight of the pigs in the truck

$1530\times 30\\ =45900\text{ ounces}\\\\=\frac{45900}{16}\\\\=2868\text{ pounds }12\text{ ounces}\\\\=1\text{ ton }868\text{ pounds }12\text{ ounces }$

So, the net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

Now, we'll find the weight of the empty truck is given by

$\text{Gross weight of a truck containing} -\text{ Net weight of pigs in the truck}\\=8\text{ tons}1123\text{ pounds}6\text{ ounces}-1\text{ton }868\text{ pounds }12\text{ounces}\\=(8\times 2000\times 16+1123\times 16+6)-(1\times 2000\times 16+868\times 16-12)\\=273974\text{ ounces}-45900\text{ ounces}\\=228074\text{ounces }\\=7\text{ tons }254\text{ pounds }10\text{ ounces}$