You would equal the equations together then solve for a variable.
-4x - 3 = -2x + 1
-4x + 2x = 1 + 3
-2x = 4
—— —-
-2 -2
x = -2
then take that x value and substitute it into any one of the equations.
Equation #1
y = -4(-2) -3
= 8 - 3
= 5
Equation #2
y = -2(-2) + 1
= 4 + 1
= 5
Answer: -4
Step-by-step explanation:
= -3 + 0 +(-2) + 3 + 2 +(-4)
= -3 - 2 + 3 + 2 - 4
= -4
We know that
surface area=area of the base+4*[area of one lateral triangle side]
area of the base=b²
b is the side length of the square
b=14 cm
area of the base=14²-----> 196 cm²
area of one lateral triangle side=b*h/2
b is the side length of the square
b=14 cm
h is the height of the lateral triangle side
h is equal to the slant height
h=15 cm
area of one lateral triangle side=14*15/2----> 105 cm²
surface area=196+4*[105]------> 616 cm²
the answer is
the surface area is 616 cm²
Answer:
10
Step-by-step explanation:
<em>Since it given that:</em>
<em>x = 7 and y = 3</em>
<em>We can substitute x and y:</em>
<em>(7-3) + 2(3)</em>
<em>7 - 3 = 4</em>
<em>4 + 2(3)</em>
<em>2(3) = 6</em>
<em>4 + 6 =10</em>
<em>Thus the answer is 10.</em>
<em />
<em>[RevyBreeze]</em>
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Answer:
Step-by-step
i) a² - 2ab + b² = (a + b)²
a² = p² ; a = p
b² = 16 = 4² ; b = 4
2ab = 2*p*4 = 8p
p² - 8p + 16 = (p - 4)²
ii) a² + 2ab + b² = (a +b)²
a² = 121x² = (11x)² ; b² = 4y² = (2y)²
2ab = 2 * 11x * 2y = 44xy
121x² + 44xy + 4y² = (11x + 2y)²
