2 years ago

Help please I will be so happy

Mathematics

1 answer:

bearhunter [10]2 years ago

7 0

The missing side length is 7.2 rounded to the nearest tenth

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What is the percent increase rounded to the nearest percent ,from 5 to 8

krok68 [10]

The increase from 5 to 8 was by 60%.

5 0

2 years ago

NEED HELP ASAP<br> NO LINKS AND NO JUST SAYING HI, PLEASE ANSWER LEGITIMATELY! THANK YOU!!!! <3

Mekhanik [1.2K]

Answer:

x=42.5

Step-by-step explanation:

First, start by setting up the equation

these are both same side interior angles, so they both add up to 180

(3x+10) + x = 180

4x+10 =180

subtract both sides by 10

-10 -10

4x=170

divide both sides by 4

x=42.5

6 0

2 years ago

Approximate the change in the volume of a sphere when its radius changes from r= 5ft to r= 5.1ft (v(r)= 3/4 pi r^3)?

leva [86]

Answer:

18.03 cubic feet

Step-by-step explanation:

Hello,

Step 1

find the volume of the sphere when radius= 5 ft

$v(r)= \frac{3}{4} \pi r^3\\v(5)= \frac{3}{4}\pi (5\ ft)^3\\v(5)= \frac{3}{4}\pi *125\ ft^{3} \\v(5)=294.52\ cubic\ feet\\$

Step 2

find the volume of the sphere when radius= 5.1 ft

$v(r)= \frac{3}{4}\pi r^3\\v(5.1)= \frac{3}{4} \pi (5.1\ ft)^3\\v(5.1)= \frac{3}{4}\pi *132.651\ ft^{3} \\v(5.1)=312.551\ cubic\ feet\\\\$

Step 3

Compare the Volumes to find the change

$\frac{v(r_{2})}{v(r_{1})} =\frac{312.551}{294.52} =1.06$

the volumen of the sphere with radius = 5.1 is 1.06 times bigger than the first one(r=5)

Now, find the change

$change= {v(r_{2})-{v(r_{1})}} \\change=312.551\ cubic\ feet\ -294.52 cubic feet \\ change=18.031\ cubic\ feet$

change=18.03 cubic feet

Have a great day.

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2 years ago

4 friends purchase 18.4 lb of peaches the peaches cost 1.75 per pound the friends share the cost of the peaches equally what amo

solong [7]

the answer is $4.60 :)

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3 years ago

Write 100 times 100 as multiplying 10 to a power by 10 to a power.

Bess [88]

Answer:

the answer is 10,000^10

Step-by-step explanation:

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3 years ago