ROUND 753 TO THE NEAREST HUNDRED.

Mathematics

2 answers:

juin [17]3 years ago

6 0

it would be 800 because you moving it up 1 so yea

frosja888 [35]3 years ago

5 0

Wouldn’t it be like 800??

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9. 2 1/8 + 1 5/12

MrMuchimi

Answer:

9) Exact Form: 85 /24 Decimal Form: 3.541 6 Mixed Number Form: 3 13 /24

10) Exact Form: 17 /18 Decimal Form: 0.9 4

11) Exact Form: 3 /5 Decimal Form: 0.6

Step-by-step explanation:

9) Convert the mixed numbers to improper fractions, then find the LCD and combine.

10) Simplify the expression.

11) To subtract fractions, find the LCD and then combine.

4 0

3 years ago

Put 45x+32=45-32 in slope interslept formthankyou.

Lilit [14]

Easy peasy pumpkineasy the answer issssssssssssssss 455555

7 0

3 years ago

I'm confused about how to find x.

NikAS [45]

Hi! so you would find x by adding the corners up to 180 degrees.

steps:
Add the corners
90+(2x+1)+(5x+5)
7x+96=180
then subtract 96 from 180
you’d get 7x = 84
then divide 7 on both sides and get x=12

7 0

3 years ago

At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu

V125BC [204]

Answer:

$\frac{^3C_1\times ^4C_1}{^{12}C_2}$

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = $^3C_1\times ^4C_1$

Also, the total combination of choosing any 2 subjects out of 12 subjects = $^{12}C_2$

Hence, the probability that a student chooses an art elective and a history elective = $\frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}$