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monitta
3 years ago
9

Help. everything is in the picture.

Mathematics
2 answers:
MariettaO [177]3 years ago
7 0

the picture is completely blank

Tpy6a [65]3 years ago
4 0
The picture is completely black:/
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7900 dollars is placed in an account with an annual interest rate of 5.5%. How much will be in the account after 11 years, to th
Lady bird [3.3K]

Answer:

\$12,679.50

Step-by-step explanation:

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=11\ years\\ P=\$7,900\\r=5.5\%=5.5/100=0.055

substitute in the formula above

A=7,900(1+0.055*11)

A=7,900(1.605)

A=\$12,679.50

4 0
3 years ago
Read 2 more answers
How do i solve this ?
lys-0071 [83]

Answer:

yo have to do nothing

Step-by-step explanation:

its 24 by the way

8 0
3 years ago
Read 2 more answers
Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.
Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

  • x-intercepts:

               (3-\sqrt{5},0) \\\\(3+\sqrt{5},0)

  • y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

    y=-x^2+6x-4

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

                 y=ax^2+bx+c

Where:    

                 a=-1;b=6;c=-4

The axis of symmetry is the vertical line with equation:

               x=-b/2a

Substitute  a=-1,\text{ and }b=6

          x=-6/[(2)(-1)]=-6/(-2)=3

Thus, the axis of symmetry is:

            x=3

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

               y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

        y=-x^2+6x-4=0

Use the quadratic equation:

       x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

         y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4

7 0
4 years ago
What is -8 square root of 9 when simplified​
gregori [183]

Answer:

\large\boxed{-8\sqrt9=-24}

Step-by-step explanation:

\sqrt{a}=b\iff b^2=a\\\\\sqrt9=3\ \text{because}\ 3^2=9\\\\-8\sqrt9=-8(3)=-24

7 0
3 years ago
Three times a number minus another number is -3. The sum of the numbers is 11. Find the numbers
MatroZZZ [7]

The first equation is

3x-y=-3

The second equation is

x+y=11

If you sum the two equations you'll cancel y:

4x=8 \iff x=2

And since the sum must be 11, we have y=9.

8 0
4 years ago
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